Answer:
2839.4 meters
Step-by-step explanation:
Given that:
Altitude = 1200 m
Using trigonometry :
The distance from point P to the airplane :
Using trigonometric relation :
Sin θ = opposite / hypotenus
Sin θ = altitude / x
Sin θ = 1200 m / x
Sin 25 = 1200 / x
0.4226182 = 1200 / x
x = 1200 / 0.4226182
x = 2839.4423
Distance from P to airplane = 2839.4 meters
The answer is
-2(u+3)-5u
-2u-6-5u
-3u-6
Cost less salvage value = 970,000 - 4500 = 965,500
Capacity of machine = 1,000,000 units.
units consumed at the end of second year = 200,000 + 300,000 = 500,000 units.
Capacity remaining = 1,000,000 - 500,000 = 500,000 units
Book value at end of second year = (500,000/1,000,000)*965,500 + 4500
= $487,250
Answer:
A
Step-by-step explanation:
the standard form of a quadratic equation is
ax² + bx + c = 0 : a ≠ 0
obtain (5 + x)(5 - x) = 7 in this form by expanding the factors
25 - x ² = 7 ( subtract 7 from both sides )
18 - x² = 0 ( multiply through by - 1 )
x² - 18 = 0 ← in standard form
with a = 1, b= 0 and c = - 18 → A
Answer:
Dr hmm fruncfyhn
Step-by-step explanation:
fudjcjdh FC hey DC KFC TV HD hmm vuejcwsm t Ufa hmm c CT DC x GB chv
