What is the remainder when x 3 - 7x - 6 is divided by the linear factor x - 4? 4 9 30 36

1 answer:

6 0

The equation, dividend, is written below,

x³ - 7x - 6

The divisor from the given is x - 4. If we are to convert this to equation, we have x = 4. In order to determine the answer to the question above, that is the remainder for the division operation, we substitute the x's of the dividend with 4.

R = (4)³ - (7)(4) - 6 = 30

The answer is the third choice, 30.

You might be interested in

In the word FLASHLIGHT what is the ratio of<br> vowels to total letters?<br> m.

Leviafan [203]

2:10
2 vowels
10 total letters

4 0

3 years ago

Read 2 more answers

What is the most important lab safety rule

Diano4ka-milaya [45]

Answer:

The most important lab safety rule is to know the location of and how to use safety equipment, such as a fire extinguisher.

Step-by-step explanation:

Hope this helps you

Crown me as brainliest:)

8 0

3 years ago

Read 2 more answers

Suppose that F is an inverse square force field below, where c is a constant.

Andre45 [30]

Answer:

Forces in our Universe

Step-by-step explanation:

First of all we have,

$F(r) = \frac{cr}{|r|^{3} }$

and,

$r = xi+yj+zk$

We need to define a function that allows us to find said change based on r, so one of the functions that shows that change is,

$f(r) = - c /|r|$

That is,

$\nabla f = F$

For this case F is a conservative field and the line integral is independent of the path. Thus, defining $P_{1} = (x_{1}, y_{1}, z_{1})$ and $P_{2} = (x_{2}, y_{2}, z_{2})$ . So the amount of work on the movement of the object from P1 to P2 is,

$W=\int\limits_c {F} \, dr$

$W= f(P_{1}-P_{2})$

$W= \frac{c}{(x_{2}^2+ y_{2}^2+ z_{2}^2)^{1/2} } -\frac{c}{(x_{1}^2+ y_{1}^2+ z_{1}^2)^{1/2}}$

$W= c(\frac{1}{d1}-\frac{1}{d2} )$

2) The gravitational force field is given by,

$F(r) =-\frac{mMGr}{ |r|^3}$

The maximum distance from the earth to the sun is $1.52*10 ^ 8$ km and the minimum distance is $1.47*10 ^ 8$ km. The mass values of the bodies are given by m = $5.97*10 ^ {24}$ kg, M = $1.99 *19 ^ {30}$ kg and the constant G is $6.67 * 10 ^{ -11 }$ $\frac{Nm ^ 2}{kg^2}$