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3 years ago

How to know which element is covalent compounds and which is ionic compounds?

Chemistry

1 answer:

Illusion [34]3 years ago

3 0

Answer:

If a compound is made from a metal and a non-metal, its bonding will be ionic.

If a compound is made from two non-metals, its bonding will be covalent.

hope that helps : )

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The atomic mass of sulfur is 32.1 amu, and the atomic mass of oxygen is 16.0 amu. To the nearest tenth of a percent, what is the

Zielflug [23.3K]

Answer:

$\%\ Composition\ of\ sulfur=40.1\ \%$

Explanation:

Percent composition is percentage by the mass of element present in the compound.

Given , Mass of sulfur= 32.1 amu

Mass of oxygen = 16.0 amu

Mass of sulfur trioxide $SO_3$ = 32.1 amu + 3*16.0 amu = 80.1 amu

$\%\ Composition\ of\ sulfur=\frac{Mass_{sulfur}}{Mass_{SO_3}}\times 100$

$\%\ Composition\ of\ sulfur=\frac{32.1\ amu}{80.1\ amu}\times 100=40.1\ \%$

6 0

3 years ago

How many atoms of phosphorus are in 8.10 mol of copper(II) phosphate?

madreJ [45]

You know from the chemical formula that 1 mole of Cu3(PO4)2 contains 2 moles of P so you can work out how many moles of P are in 8.1 moles of Cu3(PO4)2.

As for anything, 1 mole of X contains 6.022 * 10^23 of X. Multiply moles of X by Avogadro's number.

7 0

3 years ago

Read 2 more answers

You conduct an experiment that requires the creation of an ammonia solution. You do this by reacting 50.0 L of nitrogen gas with

ozzi

Answer : The molarity of the resulting ammonia solution is, 0.89 M

Explanation :

The balanced chemical reaction is:

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

First we have to calculate the moles of nitrogen gas.

As we know that at STP, 1 mole of gas occupies 22.4 L volume of gas.

As, 22.4 L volume of nitrogen gas present in 1 moles of nitrogen gas

So, 50.0 L volume of nitrogen gas present in $\frac{50.0}{22.4}=2.23$ moles of nitrogen gas

Thus, the moles of nitrogen gas is 2.23 moles.

Now we have to calculate the moles of ammonia gas.

From the reaction, we conclude that

As, 1 mole of $N_2$ react to give 2 mole of $NH_3$

So, 2.23 moles of $N_2$ react to give $2.23\times 2=4.46$ moles of $NH_3$

Now we have to calculate the molarity of the resulting ammonia solution.

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

$\text{Molarity}=\frac{\text{Moles of ammonia}}{\text{Volume of solution (in L)}}$

Now put all the given values in this formula, we get:

$\text{Molarity}=\frac{4.46mole}{5.0L}$

$\text{Molarity}=0.89M$

Therefore, the molarity of the resulting ammonia solution is, 0.89 M

7 0

3 years ago

How many grams of carbon dioxide will form if 5.5 g of C3H8 burns in 15 g of O2?

mr Goodwill [35]

C3H8+3O2--->3CO2+8H
Therefore for every 1:3 there are 3 Carbon dioxides that form. That means find the limiting reactant from the two reactants.
5.5g(1mole C3H8/44.03g of C3H8)=0.1249 moled of C3H8 and if for every one C3H8 we can form three CO2. We can assume 0.3747 miles of CO2 will be produced.
15g of O2(1 mole O2/32g of O2)=0.4685moles O2 and if for every three O2 we can produce three CO2 we may assume a 1:1 ratio.
This means C3H8 will be your limiting reactant. Therefore 0.3747 moles of CO2 will be produced.
0.3747 moles of CO2(48.01 g of CO2/1 mole of CO2)= 17.99 grams of CO2

5 0

4 years ago

Why should you pay attention to the physical states of reactants and products when writing elquilibrium constant expressions?

babunello [35]

Answer is: because pure liquids (shown in chemical reactions by appending (l) to the chemical formula) and solids (shown in chemical equations by appending (s) to the chemical formula) not go in to he equilibrium constant expression, only gas state (shown in chemical reactions by appending (g) to the chemical formula) reactants and products go in to he equilibrium constant expression.
For example, equilibrium constant expression Kp for reaction:
A(s) + 2B(s) ⇄ 4C(g) + D(g).
will be: Kp = [C]⁴·[D].
But for reaction A(g) + 2B(g) ⇄ 4C(g) + D(g), will be:
Kp = [C]⁴·[D] / [A]·[B]².

3 0

4 years ago

How to know which element is covalent compounds and which is ionic compounds?​

How to know which element is covalent compounds and which is ionic compounds?