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3 years ago

How many grams of carbon dioxide will form if 5.5 g of C3H8 burns in 15 g of O2?

1 answer:

5 0

C3H8+3O2--->3CO2+8H
Therefore for every 1:3 there are 3 Carbon dioxides that form. That means find the limiting reactant from the two reactants.
5.5g(1mole C3H8/44.03g of C3H8)=0.1249 moled of C3H8 and if for every one C3H8 we can form three CO2. We can assume 0.3747 miles of CO2 will be produced.
15g of O2(1 mole O2/32g of O2)=0.4685moles O2 and if for every three O2 we can produce three CO2 we may assume a 1:1 ratio.
This means C3H8 will be your limiting reactant. Therefore 0.3747 moles of CO2 will be produced.
0.3747 moles of CO2(48.01 g of CO2/1 mole of CO2)= 17.99 grams of CO2

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3 years ago

Convert 78.9 kJ into calories Can you also explain how pls? ty

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Explanation:

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3 years ago

An inexpensive and accurate method of measuring the quantity of electricity flowing through a circuit is to pass the current thr

Paha777 [63]

Total of 127.013 C of charge is passed

Given

weight of Ag solution before current has passed = 1.7854 g

weight of Ag solution after current has passed = 1.8016 g

Molecular mass of Ag = 107.86 g

Faraday's Constant = 96485

First of all we have to apply Faraday's First Law of Electrolysis i.e

m = ZQ

where

Z is propotionality constant (g/C)

Q is charge (C)

Hence,

Z = Atomic mass of substance/ Faraday's Constant

= $\frac{107.86 g}{96485 C}$

= 0.0011178 g/C

Now ,

change in mass before and after the passing of current (Δm)

Δm = 1.8016g-1.7854g

= 0.0162g

Now amount of coulombs passed = $\frac{0.142g}{0.0011178 g/C }$

amount of coulombs passed = 127.03524 C

Thus from the above conclusion we can say that amount of coulombs have passed is 127.03524 C

Learn more about Electrolysis here: brainly.com/question/16929894

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2 years ago