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Kazeer [188]
3 years ago
15

How many grams of carbon dioxide will form if 5.5 g of C3H8 burns in 15 g of O2?

Chemistry
1 answer:
mr Goodwill [35]3 years ago
5 0
C3H8+3O2--->3CO2+8H
Therefore for every 1:3 there are 3 Carbon dioxides that form. That means find the limiting reactant from the two reactants.
5.5g(1mole C3H8/44.03g of C3H8)=0.1249 moled of C3H8 and if for every one C3H8 we can form three CO2. We can assume 0.3747 miles of CO2 will be produced.
15g of O2(1 mole O2/32g of O2)=0.4685moles O2 and if for every three O2 we can produce three CO2 we may assume a 1:1 ratio.
This means C3H8 will be your limiting reactant. Therefore 0.3747 moles of CO2 will be produced.
0.3747 moles of CO2(48.01 g of CO2/1 mole of CO2)= 17.99 grams of CO2
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Answer:

In the explanation

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Hope this helps!

5 0
2 years ago
What is the molar mass of cholesterol if 0.00105 mol weighs 0.406 g?
goblinko [34]
<h3>Answer: 386.67 g/mol </h3>

Explanation:

Molar Mass = Mass ÷ Mole

                   =  0.406 g ÷ 0.00105 mol

                   =  386.67 g/mol

∴ molar mass of cholesterol = 386.67 g/mol

5 0
2 years ago
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