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3 years ago

15

What is the time and space margin that is the distance you can see ahead of your vehicle?

1 answer:

IgorLugansk [536]3 years ago

5 0

The space margin depends on light and weather conditions as well as terrain (road curvature, hills, trees or other obstacles).

The time margin depends on the space margin, your reaction time, and your speed of travel.

You may appear to have a lot of time or space in icy conditions, but that can be an illusion. A collision course on ice will result in a collision, regardless of the time or distance involved.

Insufficient information is provided to be more specific.

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What is the value of the rationale expression below when x is equal to 4? X+20/x+4

sveta [45]

Answer:

3

Step-by-step explanation:

to evaluate substitute x = 4 into the rational expression, that is

$\frac{4+20}{4+4}$ = $\frac{24}{8}$ = 3

6 0

2 years ago

QUESTION 6 / 10

Nadya [2.5K]

Answer:

b. The stipend you receive.

Step-by-step explanation:

It would say paid intern if they were paid.

7 0

2 years ago

How do I solve this?

iris [78.8K]

Answer:

Step-by-step explanation:

From the picture attached,

Addition of the blocks in first row is 60

a + a + a + 12 = 60

3a + 12 = 60

3a = 60 - 12

3a = 48

a = 16

For second row,

(b + 5) + (b + 5) + (b + 5) + (b + 5) = 60

4(b + 5) = 60

b + 5 = 15

b = 10

For third row,

(a + b) + c = (b + 5) + (b + 5) + (b + 5)

a + b + c = 3(b + 5)

16 + 10 + c = 3(10 + 5) [Since, a = 16 and b = 10}

26 + c = 45

c = 45 - 26

c = 19

For fourth row,

3c + d = 60

3(19) + d = 60

57 + d = 60

d = 60 - 57

d = 3

8 0

2 years ago

What is the probability that a data value in a normal distribution is between a z-score of -1.32 and a z-score of -0.34 Round yo

Galina-37 [17]

We are asked to find the probability that a data value in a normal distribution is between a z-score of -1.32 and a z-score of -0.34.

The probability of a data score between two z-scores is given by formula $P(a$ .

Using above formula, we will get:

$P(-1.32$

Now we will use normal distribution table to find probability corresponding to both z-scores as:

$P(-1.32$

$P(-1.32$

Now we will convert $0.27351$ into percentage as:

$0.27351\times 100\%=27.351\%$

Upon rounding to nearest tenth of percent, we will get:

$27.351\%\approx 27.4\%$

Therefore, our required probability is 27.4% and option C is the correct choice.

5 0

3 years ago

HELP PLZZZZ like asap

Anestetic [448]

Answer:

The answer is B

Step-by-step explanation:

✌

7 0

3 years ago

Read 2 more answers