Here are my answers to the given questions above:
Part 1. Here is my example of a real life scenario that describes what is happening. Let us say, I have 2 cookies and the bottle of milk costs 11 dollars, and 3 cookies and 4 bottles of milk cost 24 dollars.
Part 2.
y=11-2x
3x+4(11-2x)=24
3x+44-8x=24
-5x=-20
x=4
y=11-8
y=3
Therefore, each cookie costs 4 dollars, and a bottle of milk costs 3 dollars.
Hope this answer helps. Let me know if you need more help next time.
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Answer:
The mixtures are not proportional.
3 fluid ounces of vinegar has to be added in the second mixture to make it proportional to the first mixture.
its =3
Step-by-step explanation:
The one mixture contains 6 fluid ounces and 10 fluid ounces of water and vinegar respectively.
Therefore, the ratio of water to vinegar in the first mixture is 6 : 10 = 3 : 5
Now, a second mixture contains 9 fluid ounces of water and 12 fluid ounces of vinegar.
Hence, the ratio of water to vinegar in the second mixture is 9 : 12 = 3 : 4
Therefore, the mixtures are not proportional.
Therefore, we have to add x fluid ounces of vinegar to the second mixture to make it in the ratio of 3 : 5.
So,
⇒ 12 + x = 15
⇒ x = 3 fluid ounces.
Therefore, 3 fluid ounces of vinegar has to be added in the second mixture to make it proportional to the first mixture. (Answer
Answer: option d. x = 3π/2Solution:function y = sec(x)
1) y = 1 / cos(x)
2) When cos(x) = 0, 1 / cos(x) is not defined
3) cos(x) = 0 when x = π/2, 3π/2, 5π/2, 7π/2, ...
4) limit of sec(x) = lim of 1 / cos(x).
When x approaches π/2, 3π/2, 5π/2, 7π/2, ... the limit →+/- ∞.
So, x = π/2, x = 3π/2, x = 5π/2, ... are vertical asymptotes of sec(x).
Answer: 3π/2
The figures attached will help you to understand the graph and the existence of multiple asymptotes for y = sec(x).
Four times the sun of twice a number and -3
Answer:
A relation is a subset of cartesian product of two non empty sets whereas A function is a type of relation in which every element of first set has one and only image in the second set.
In a relation an element of the first set can have many images in the second set whereas in a function the first element can have only one image in the second set.
The given relation is not a function as the element 1 is related to 3 different elements in the second set.
Domain={1}
Range={7,14,21}
