Y2-y1/x2-x1
(1,14) & (3,4)
y2= 4
y1=14
x2=3
x1=1
So....
(4-14)/(3-1) = -10/2 = -5
The answer should be negative instead of positive, she probably subtracted 4 from 14 instead.
Common Pythagorean triples include
(3, 4, 5)
(5, 12, 13)
(7, 24, 25)
(9, 40, 41)
The only Pythagorean triple that is an arithmetic sequence is (3, 4, 5), so any arithmetic sequence that is a Pythagorean triple must be a multiple of that, such as (9, 12, 15) or (15, 20, 25).
The arithmetic sequences of selections B and D are unrelated to the (3, 4, 5) triple, so cannot be Pythagorean triples. For selection A, we know that 9² + 11² = 81 + 121 = 202 > 14², so that is not a right triangle.
The appropriate selection is ...
C. 7, 24, 25
Answer:
Step-by-step explanation:
Given:
Center of circle is at (5, -4).
A point on the circle is 
Equation of a circle with center 
and radius 'r' is given as:
Here, 
Radius of a circle is equal to the distance of point on the circle from the center of the circle and is given using the distance formula for square of the distance as:
Using distance formula for the points (5, -4) and (-3, 2), we get
Therefore, the equation of the circle is:
Now, rewriting it in the form asked in the question, we get
5,7 and 8 are right angles, and 6 is an acute angle this is because of u look at 9 and 10 you can see a little box looking thing under the h and if u do that to all of them 5, 7 and 8 can fit the little box but 6 you can’t because it is an acute angle. Hope this helped!
The equation factored would be (x+7)(x-2). As 7-2=5 and (7)(2)=14.
