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Keith_Richards [23]
3 years ago
13

One cubic meter of water weighs approximately 2200 pounds. There are 100 cm in one meter. If you have a box-shaped fish tank tha

t measures 30 cm by 30 by 80 cm, what is the weight of the water that can be held in the tank?
Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
3 0

Answer:

158.4 pounds

Step-by-step explanation:

first find the volume of the tank

V = 30 \times 30 \times 80

V = 72000 cm^3

to convert this to m^3 we know that 1m = 100cm

V = 72000 cm^3 \times \left(\dfrac{1\,\text{m}}{100\,\text{cm}}\right)^3

V = 72000 cm^3 \times \left(\dfrac{1\,\text{m}^3}{100^3\,\text{cm}^3}\right)

the cm^3 cancel out.

V = \dfrac{72000}{100^3} m^3

V = 0.072\,m^3

by simply converting the side-lengths to meters beforehand can give you this answer directly:

V = 0.3 \times 0.3 \times 0.8 = 0.072 m^3

it is given that 1 meter cube of water weighs about 2200 pounds.

1\,m^3 = 2200 \,\text{lb}

multiply both sides with 0.072 to find our answer:

1\,m^3 \times 0.072 = 2200 \times 0.072 \,\text{lb}

0.072\,m^3 = 158.4 \,\text{lb}

hence the weight of the water in the tank would be 158.4 pounds!

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Behind my math class help pls
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Answer:

Please check the explanation.

Step-by-step explanation:

Part a)

Given that the two parallel lines are crossed by a transversal line.

Given that

m∠2 = 2x + 54 and m∠6 = 6x - 11

Angle ∠2 and ∠6 are corresponding angles.

Corresponding angles are congruent.

Thus,

m∠2 = m∠6

2x + 54 = 6x - 11

flipe the equation

6x - 11 = 2x + 54

subtract 2x from both sides

6x - 2x - 11 = 2x - 2x + 54

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4x - 11 + 11 = 54 + 11

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4x/4 = 65/4

x = 16.2500    (round to 4 decimal places)

Part b)

We have already determined

x = 16.2500

Given

m∠2 = 2x + 54

substitute x = 16.2500 in the euation

        = 2(16.2500) + 54

        = 86.5°

As angle ∠2 and angle ∠1 lie on a straight line. Hence, the sum of their angles must be 180°.

i.e.

m∠1 + m∠2 = 180°

substituting m∠2 =  86.5° in the equation

m∠1 + 86.5°  = 180°

subtracting 86.5° from both sides

m∠1 + 86.5° - 86.5° = 180° - 86.5°

m∠1 = 93.5°

Therefore, the measure of angle m∠1 is:

  • m∠1 = 93.5°
4 0
3 years ago
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