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Keith_Richards [23]
3 years ago
13

One cubic meter of water weighs approximately 2200 pounds. There are 100 cm in one meter. If you have a box-shaped fish tank tha

t measures 30 cm by 30 by 80 cm, what is the weight of the water that can be held in the tank?
Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
3 0

Answer:

158.4 pounds

Step-by-step explanation:

first find the volume of the tank

V = 30 \times 30 \times 80

V = 72000 cm^3

to convert this to m^3 we know that 1m = 100cm

V = 72000 cm^3 \times \left(\dfrac{1\,\text{m}}{100\,\text{cm}}\right)^3

V = 72000 cm^3 \times \left(\dfrac{1\,\text{m}^3}{100^3\,\text{cm}^3}\right)

the cm^3 cancel out.

V = \dfrac{72000}{100^3} m^3

V = 0.072\,m^3

by simply converting the side-lengths to meters beforehand can give you this answer directly:

V = 0.3 \times 0.3 \times 0.8 = 0.072 m^3

it is given that 1 meter cube of water weighs about 2200 pounds.

1\,m^3 = 2200 \,\text{lb}

multiply both sides with 0.072 to find our answer:

1\,m^3 \times 0.072 = 2200 \times 0.072 \,\text{lb}

0.072\,m^3 = 158.4 \,\text{lb}

hence the weight of the water in the tank would be 158.4 pounds!

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3 years ago
John can type 45 words per min (45/min) he has to type a report for Mrs. Ramey that must be 2700 words. How many hours will it t
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Answer:

It will take 1 hour to type the report.

Step-by-step explanation:

The time that will take to John to type the report is:

\frac{1 min}{45 w}*2700 w = 60 min

Since we have 60 minutes in 1 hour, the time in hours is:

\frac{1 h}{60 min}*60min = 1 h

Therefore, it will take 1 hour to type the report.

I hope it helps you!

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3 years ago
❤️❤️help please ASAP❤️❤️
Setler [38]
Using the Pythagorean theorem a^2 +b^2 = c^2, where a and b are the sides of a triangle and c is the hypotenuse.

BA and AC are sides and BC is the hypotenuse.

we have 23^2 + b^2 = 45^2

529 + b^2 = 2025

b^2 = 2025 - 529

b^2 = 1496

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b = 38.68 = 38.7

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1. La asistencia a un juego de béisbol profesional fue de 4500 personas y el dinero
Elena-2011 [213]

Resolviendo un sistema de ecuaciones veremos que se vendieron 900 boletos de $15 y 3600 boletos de $10.

<h3> ¿Cuántos boletos de cada tipo se vendieron?</h3>

Primero definamos las variables:

  • x = número de bolteos de $10 vendidos.
  • y = número de bolteos de $15 vendidos.

Sabemos que se vendieron 4500 boletos, entonces:

x + y = 4500

Y se recaudo un total de $49,500, entonces:

x*$10 + y*$15 = $49,500

Entonces tenemos un sistema de ecuaciones:

Para resolver esto, primero debemos aislar una de las variables en la primer ecuación, voy a aislar x:

x = 4500 - y

Ahora reemplazamos esto en la otra ecuación:

(4,500 - y)*$10 + y*$15 = $49,500

Ahora debemos resolver estoy para y.

$45,000 - y*$10 + y*$15 = $49,500

y*$5 = $49,500 - $45,000 = $4,500

y = ( $4,500)/$5 = 900

Entonces:

x = 4500 - 900 = 3600

Se vendieron 900 boletos de $15 y 3600 boletos de $10.

Sí quieres aprender más sobre sistemas de ecuaciones:

brainly.com/question/13729904

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