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sdas [7]
3 years ago
8

Como resolver 4 2/3 - 1 1/2 +7

Mathematics
2 answers:
Maru [420]3 years ago
8 0
35/3 - 1 1/2
Hope I help you. 
Good luck :)
noname [10]3 years ago
6 0
35/3 - 11/2 that is the answer
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Torque (or moment) is the measure of turning force or twist on an object. If a mechanic is applying 12 Newton centimeters of tor
SashulF [63]

Answer:

1.0638

Step-by-step explanation:

Given the question:

If a mechanic is applying 12 Newton centimeters of torque on a bolt how many pound inches would this be?

Torque = 12 Newton centimeter

Torque which is the turning effect on an object :

1 Newton = 0.225 pound force

1 centimeter = 0.394 inch

Hence ;

1 Newton centimeter = (1 × 0.225 × 0.394) = 0.08865 pound inch

12 Newton centimeter is hence, equals :

(12 × 0.225 × 0.394) pound inch

= 1.0638 pound inch

7 0
3 years ago
Nika earns a gross pay of $73,000. Her total employee benefits are 22% of her gross pay and she has no job expenses. If Nika get
algol [13]

Answer:

Actually, your correct answer is C. just took the test :)

8 0
4 years ago
Read 2 more answers
Which of these figures has rotational symmetry?
Bumek [7]

Hello!

The answer is a.

Good luck! :)

8 0
3 years ago
Shauna makes 24 cupcakes per hour. She has already made 48 cupcakes. Let x represent the amount of time Shauna spends making the
GalinKa [24]
Y=24x+48

24 per hour (x) plus the 48 she already made would equal a total (y).
3 0
3 years ago
We assume each month is equally likely to be a student’s birthday month. i) The number of ways ten students can have birthdays i
snow_lady [41]

Answer:

The solutions are correct

Step-by-step explanation:

i) In a year there is a total of 12 months, if ten students can have birthdays in 10 different months, the number of ways this can happen is:

Number of ways = 12 × 11 × 10 × . . . × 3 = \frac{12!}{2!}

ii) The number of ways 1 student can have birthday months = 12¹, The number of ways 2 students can have birthday months = 12¹ × 12¹ = 12². Hence:

The number of ways 10 students can have birthday months = 12¹⁰

iii) The probability that no two share a birthday month = \frac{12!}{2!*12^{10}} = 0.00387

7 0
3 years ago
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