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3 years ago

Where can the medians of a triangle intersect

Mathematics

1 answer:

gizmo_the_mogwai [7]3 years ago

6 0

In side the triangle. Each median is split in the ratio 2:1 by the intersection.

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Simplify the problem ( 3 over 5 to the power of negative 3

sweet-ann [11.9K]

$(\frac{3}{5})^-^3$

First you had to used their apply exponent rule.

And it gave us ⇒ $(\frac{5}{3})^3$

Then apply exponent rule again.

And it gave us ⇒ $\frac{5^3}{3^3}$

$125=5^3=5*5*5=125$

$=\frac{125}{3^3}$

$27=3^3=3*3*3=27$

$=\frac{125}{27}$

Final answer: ⇒ $\boxed{125/27}$

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

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3 years ago

6th grade work guys!! (:

kirill [66]

Answer:

The answer is C I think???

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Brian is playing a carnival game. He is blindfolded while he throws a dart at a board of 12 balloons, as shown below. Each ballo

Vadim26 [7]

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7 0

3 years ago

I will give brainliest

sweet [91]

Is this correct? im not sure about the second ques

3 0

3 years ago

A parabola has an x-intercept of -1, a y-intercept of -3, and a minimum of -4 at x = 1.

torisob [31]

Answer:

The graph in the attached figure

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

$y=a(x-h)^{2}+k$

where

a is a coefficient

(h,k) is the vertex

In this problem we have

(h,k)=(1,-4)

substitute

$y=a(x-1)^{2}-4$

we have

An x-intercept of (-1,0)

substitute and solve for a

$0=a(-1-1)^{2}-4$

$0=4a-4$

$4a=4$

$a=1$

The equation is

$y=(x-1)^{2}-4$

<u><em>Verify the y-intercept</em></u>

For x=0

$y=(0-1)^{2}-4$

$y=-3$

The y-intercept is the point (0,-3) -----> is correct

using a graphing tool

see the attached figure

4 0

4 years ago