<h3>Answer 1a :- </h3>
Here we can solve this question using<em> </em><em>Unitary</em><em> </em><em>Method</em><em> </em><em>.</em> As ;
→ In 17hrs the boat travels 452km
→ In 1hr the boat will travel 452km/17
→ In 9hrs the boat will travel 452/17km * 9 = 239.29km
<h3>Answer 1b:-</h3>
→ A car can travel 156km on 13L gasoline .
→ It will travel 1km on 13/156L of gasoline .
→ It will travel 480km on 13/156*480L = 40L of gasoline .
<h3>
Answer 2a :-</h3>
→ A boat can go 180 miles on 60L gasoline.
→ It will go 1mile in 60/180L of gasoline.
→ It will go 306 miles in 60/180*306L = 102L of gasoline .
<h3>Answer 2b :-</h3>
→ On 51L of gasoline a car can go 408km
→ On 1L of gasoline car will go 408/51 km
→ On 11L of gasoline it will go 408/51*11L = 88km
Answer:
The final price paid by Samantha is 55.25 $
Step-by-step explanation:
In order to find out the final price of the jacket for Samantha we need to calculate how much 35% of 85 $ is and subtract the original price by it. So we have:
price of discount = 85*(35%) = 85*(35/100) = 85*(0.35) = 29.75 $
Now we can compute the final price by subtracting the original price by the price of discount. So we have:
final price = original price - price of discount = 85 - 29.75 = 55.25 $
Answer:
3135
Step-by-step explanation:
Givens
a1 = 6
Use t4 - t3 to get d
t4 = 27
t3 = 20
Step One
Find a1 and d
a1 = 6
d = t4 - t3
d = 27 - 20
d = 7
Step Two
Find the 30th Term
tn= a1 + (n -1 )*d
t30 = 6 + (30 - 1) * 7
t30 = 6 + 29*7
t30 = 6 + 203
t30 = 209
Step Three
Find the sum using Sum = (a + t30)*n/2
n = 30 given
a1 = 6 given
t30 = 209 calculated from step 2
Sum = (a1 + t30)*n/2 Substitute
Sum = (6+ 209)*30/2 Combine like terms and divide by 2
sum = 215 * 15 Multiply
Sum = 3135 Answer
