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2 years ago

Don't understand the question.

Mathematics

2 answers:

Finger [1]2 years ago

8 0

The solution is D.
From the top right & left corners drop a perpendicular line to the base forming right triangles on the right and left sides. This makes the center [art of the base 12 and the base of the triangles 7. Use the Pythagorean Theorem to find the altitude, which is the same as the height.
7^2 + b^2 = 25^2
b^2 = 25^2 - 7^2
b = 24

Doss [256]2 years ago

6 0

H=2 A/a+b try solving the problem using this formula....sorry I couldn't answer the question

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Viefleur [7K]

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the son. and 7/20

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1 year ago

Please help me !!! i will mark brain-list for the correct answer !!!

Shtirlitz [24]

Answer:

Step-by-step explanation:

So remember that a quarter of a circle is 90 degrees, a half of a circle is 180 degrees, and a whole circle is 360 degrees.

Looking at the image shown, it must be half a circle, whihc is 180 degrees. The image tells us that the 1st angle is 7 degrees. Now, we must find the 2nd angle.

Heres what we know however:

angle 1 + angle 2 = 180 degrees.

How do we know this?

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Lets input that into our nice lil equation to get an answer:

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2 years ago

Root 3 cosec140° - sec140°=4 prove that

Lorico [155]

Answer:

Step-by-step explanation:

We are to show that $\sqrt{3} cosec140^{0} - sec140^{0} = 4\\$

Proof:

From trigonometry identity;

$cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}$

$\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\$

From trigonometry, 2sinAcosA = Sin2A

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