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3 years ago

The following represents a tetrahedron.

Mathematics

1 answer:

aivan3 [116]3 years ago

8 0

Answer:

It's the second and third one!!

Step-by-step explanation:

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The student population of a school consists of 300 girls and 500 boys

denis-greek [22]

Answer:

In all you have 800 students.

The ratio of girls to boys is 300:500

500 x 300 = 150000

Step-by-step explanation:

Hope this helps?

8 0

3 years ago

Please help and thx .

alex41 [277]

Answer:

n=o

Step-by-step explanation:

3 0

3 years ago

If A is a 3×3 singular matrix such that λ1=1−i is an eigenvalue of A, then the other eigenvalues of A are 0,1+i

astra-53 [7]

Answer:

1 + i

Step-by-step explanation:

Given that A is a 3 * 3 singular matrix

one of its eigenvalue ( λ1 ) = 1 - i

Given that the determinant of a singular matrix is = 0

therefore the second eigen value ( λ2 ) = 1 + i

1 - i + 1 + i = 0

5 0

2 years ago

There was a country concert held at the park. For every 3 men there were 5 women that went to the concert. If 30 more women atte

8090 [49]

Answer:

3m == 5w, that means for such unit, there is a 2 person difference

30 person difference = 30/2 = 15units

and again one unit means 3m and 5w

so 15*3men, and 15*5women

and you can check the difference is 30

8 0

3 years ago

The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f

WITCHER [35]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

The picture of the question in the attached figure

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)\\C=6\pi\ cm$

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

$AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

4 0

3 years ago