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riadik2000 [5.3K]
4 years ago
9

Expressions with and without Parenthesesmutation andonSeeMore​

Mathematics
1 answer:
dexar [7]4 years ago
5 0

Answer:

Step-by-step explanation:

each part makes how you can show by what to do on mathematics by fractions and unit fractions with multiplication.

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a hockey puck travels at a constant speed of 20m/s. what is the speed in mi/h? round to the nearest hundredth.
Mandarinka [93]
60 Seconds=1 Minute
60 Minutes=3600 Seconds
1 Meter=0.000621371 Miles
20*3600=72000 meters
72000/0.000621371= 44.738726 Mi/H
Boom!
6 0
4 years ago
58.7 is what percent of 1,000
lesya [120]
Just move the decimal place to the left for each 0 in your number.
The answer is 5.87
5 0
4 years ago
Read 2 more answers
It is known that 70% of the customers in a sporting goods store purchase a pair of running shoes. A random sample of 25 customer
gogolik [260]

Answer:

=BINOMDIST(10,25,70%,FALSE) -BINOMDIST(5,25,70%,FALSE)

0.001324586

Step-by-step explanation:

The success probability is p = 70% = 0.70

The number of trials are n = 25

The Excel formula for the binomial distribution is given by

BINOMDIST(Number_s, Trial_s, Probability_s, Cumulative)

Where

Numbers = 5 and 10

Trials = 25

Probability = 70%

Cumulative = FALSE

The probability of between 5 and 10 customers is then

=BINOMDIST(10,25,70%,FALSE) -BINOMDIST(5,25,70%,FALSE)

0.001324586

Note: FALSE option provides the probability of exactly 10 and 5 where TRUE option gives cumulative results (0 to 5 or 0 to 10) that would be wrong in this case.

6 0
3 years ago
What is the remainder of 203 divided by 9?
ra1l [238]

203/9=22 with a remainder of 5

3 0
3 years ago
The Hickory Stick has a selection of 3 meats and 6 vegetables. How many different selections of one meat and one vegetable are p
valentina_108 [34]

The <u>different</u> selections of<u> one</u> meat and <u>one</u> vegetable are possible are 18 selections.

Since the Hickory Stick has a selection of 3 meats and 6 vegetables, the number of ways we can select <u>one </u>meat out of 3 is ³C₁ = 3.

Also, the number of ways we can select <u>one </u>vegetable out of 6 is ⁶C₁ = 6.

So, the total number of selections of <u>one</u> meat and <u>one</u> vegetable is ³C₁ × ⁶C₁ = 3 × 6

= 18 selections

So, the <u>different</u> selections of<u> one</u> meat and <u>one</u> vegetable are possible are 18 selections.

Learn more about combination here:

brainly.com/question/19341024

7 0
2 years ago
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