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balandron [24]
2 years ago
14

What is the answer to 0.9 divided by 7.02

Mathematics
1 answer:
Studentka2010 [4]2 years ago
5 0

Answer:

0.128205128 or 1

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Finding an Equation of a tangent Line in Exercise, find an equation of the tangent line to the graph of the function at the give
frutty [35]

Answer:

y=\dfrac{3x}{e}+\dfrac{4}{e}

this is the equation of the tangent at point (-1,1/e)

Step-by-step explanation:

to find the tangent line we need to find the derivative of the function g(x).

g(x) =e^{x^3}

  • we know that \frac{d}{dx}(e^{f(x)})=e^{f(x)}f'(x)

g'(x) =e^{x^{3}}(3 x^{2})

g'(x) =3 x^{2} e^{x^{3}}

this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'

to find the slope at (-1,1/e) we'll use the x-coordinate of the point i.e. x = -1

m =3 (-1)^{2} e^{(-1)^{3}}\\m =3e^{-1}\\m=\dfrac{3}{e}

using the equation of line:

(y-y_1)=m(x-x_1)

we'll find the equation of the tangent line.

here (x1,y1) =(-1,1/e), and m = 3/e

(y-\dfrac{1}{e})=\dfrac{3}{e}(x+1)\\y=\dfrac{3x}{e}+\dfrac{3}{e}+\dfrac{1}{e}\\

y=\dfrac{3x}{e}+\dfrac{4}{e}

this is the equation of the tangent at point (-1,1/e)

3 0
3 years ago
Can someone please help me with this proof?!
Elza [17]

Answer:

because AC and BD bis => AX = XC; BX = XD

ΔAXD ≅ ΔCXB (SAS) because: AX = CX

                                                    DX = BX

                                                    m∠AXD = m∠BXC ( 2 opposing angles)

because ΔAXD ≅ ΔCXB (SAS)

=> AD = BC and m∠DAX = m∠BCX

because m∠DAX = m∠BCX => AD//BC

ABCD has AD = BC and AD//BC => ABCD is a parallelogram

Step-by-step explanation:

4 0
3 years ago
Help me with my last question plz
fomenos

Answer:

57

Step-by-step explanation:

Angle IHK and JKH are alternate angles.

Alternate angles are equal

3 0
3 years ago
Use the decimals 2.47, 9.57 and 7.1 to write two different addition facts and two different subtraction facts
netineya [11]
2.47 + 7.1
7.1 + 2.47

9.57-7.1
9.57-2.47
6 0
3 years ago
How many pounds of mixed nuts that contain 70% peanuts must Shannon add to 15 pounds of mixed peanuts that contain 20% peanuts t
Degger [83]

Answer:

10 pounds.

Step-by-step explanation:

Let x pounds be the amount of mixed nuts we require.

Amount of peanuts in this mix = 0.70x pounds. Amount of peanuts in the 20% mix = 0.20*15 = 3 pounds.

So we have the equation:-

0.70 x + 3 = 0.40(x + 15)

0.70 x + 3 = 0.40(x + 15)

0.70x + 3 = 0.40x + 6

0.70x - 0.40x = 6 - 3

0.30x = 3

x = 10.

8 0
3 years ago
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