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amid [387]
2 years ago
13

Sarah's grape vine grew 15 inches in 6 weeks, write an equation to represent its growth after x weeks

Mathematics
1 answer:
mixer [17]2 years ago
5 0
6x = 15

I apologize if this is wrong!
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Simplify this algebra expression:<br><br> 6j-2j-2j+8+9+6e+5
ELEN [110]

Answer:

6j-2j-2j+8+9+6e+5

= 6j - 4j + 6e + 24

= 2j + 6e + 24

8 0
1 year ago
Read 2 more answers
A(n)=3/2(-2)^(n-1). What is the 3rd term in the sequence?
Angelina_Jolie [31]

Answer:

6

Step-by-step explanation:

Substitute n for 3

A(n) = 3/2(-2)^(n-1)

A(3) = 3/2(-2)^(3-1)

A(3) = 3/2(-2)²

A(3) = 3/2(4)

A(3) = 12/2

A(3) = 6

3 0
3 years ago
Read 2 more answers
A manufacturer of skis produces two types: downhill and cross country. The times required for manufacturing and finishing each s
pogonyaev

Answer:

So to maximize profit 24 downhill and 20 cross country shouldbe produced

Step-by-step explanation:

Let X be the number of downhill skis and Y the number of cross country skis.

Time required for manufacturing and finishing each ski are: manufacturing time per ski, downhill 2.5 hours, cross country 1.5 hours

Finishing time per ski: downhill 0.5 hours, cross country 1.5 hours.

Total manufacturing time taken = (2.5) x+ (1.5+) y = 2.5x+1.5y≤90

total finishing time taken = 0.5x+1.5 y≤42

Profit function

Z = 50x+50y

Objective is to maximize Z

Solving the two equations we get intersecting point is

(x,y) = (24,20)

In the feasible region corner points are (0.28) (36,0)

Profit for these points are

i) 2200 for (24,20)

ii) 1400 for (0,28)

iii) 1800 for (36,0)

So to maximize profit 24 downhill and 20 cross country shouldbe produced.

6 0
3 years ago
Graph it pleaseeeeeeeeeeeeeeeeeeeeeeeeeeee
mina [271]

Answer:

Step-by-step explanation:

5c + 4f ≥ 200

c + f ≤ 60

c > 0

f > 0

5 0
2 years ago
Write the equation for a line in standard form (Ax+By+C) that is perpendicular to y = 3x -
salantis [7]

Answer:

x+3y-6=0

Step-by-step explanation:

given eqn is y=3x-2 which is 3x-y-2=0

the eqn of line perpendicular to given eqn is -x+3y+k=0

it passes through (6,4)

-6+3*4+k=0

or,. -6+12+k=0

or, k= -6

therefore, the eqn of line perpendicular to given eqn is x+3y-6=0

8 0
3 years ago
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