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3 years ago

Solve the equation f/6= 2.5

Mathematics

1 answer:

dezoksy [38]3 years ago

3 0

Answer:

f=15

Step-by-step explanation:

f/6=2.5

f=2.5*6

f=15

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NikAS [45]

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2 years ago

Does anyone know how to do this? And can you also help me with this problem, thank you :)

GenaCL600 [577]

<span>Multiply equation(2) with 4 so that coefficient of become same in both the equations(You can make coefficient of y same and can follow the following procedure.)
</span><span>* Subtract (3) from (1)
* </span>Divide both sides by -19
*Subtract 21 from both sides.
*Divide both sides by 4
so the solution is x= 3 and y= -7
Hope I helped you :)

6 0

3 years ago

CAN SOMEONE PLEASE HELP ME WORTH 20 points

Ainat [17]

Answer:

12 units

Step-by-step explanation:

Point H is the intersection of the medians, so divides each median into parts with the ratio 2:1. Here, that is ...

CH : HG = 2 : 1 = CH : 6

Then CH = 2×6 = 12.

_____

Alternatively, you could determine altitude CG from the Pythagorean theorem applied to triangle BCG. You would compute ...

CG² +GB² = BC²

CG = √(BC² -GB²) = √(19.8² -8²) = √146.7 ≈ 12.1

This is an approximation based on the fact that the value 9.9 for BF is an approximation. Based on BG and GH being integer values, the appropriate measure of BF is (√388)/2 ≈ 9.8489.

(The triangle shown cannot exist.)

5 0

2 years ago

Which is the interval notation represent the domain?

Kazeer [188]

Answer:

The first choice, $(-\infty, 7) \cup (7, \infty)$ .

Step-by-step explanation:

The dashed vertical line is a vertical asymptote. The x-coordinate of all points on this vertical asymptote are equal to 7. In other words, when the x-value of a point on the graph approaches $7$ , its y-value approaches infinity (or negative infinity.)

Either way, the graph is not defined for $x = 7$ . The point $7$ should thus be excluded from the domain of the graph.

The graph is apparently defined for all other x-values. The domain of the function should thus be all real numbers with the exception of $x = 7$ . Here's how to write that in interval notation:

The set of all real numbers can be expressed as the interval $(-\infty, \infty)$ . Note that infinity $\infty$ (or $(- \infty)$ itself isn't a real number. The round brackets indicate that both endpoints are excluded from the from the interval.
The set of all real numbers less than (not equal to) $7$ is $(-\infty,7 )$ (both ends are excluded.) The set of all real numbers greater than (not equal to) $7$ is $(7, \infty)$ .
The set of all real numbers that is not equal to $7$ is the union of all real numbers less than $7$ and all real numbers greater than $7$ . The union operator $\cup$ connects two intervals.

In other words, the domain is $(-\infty, 7) \cup (7, \infty)$ .

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3 years ago

Cual es la forma más simple al efectuar la operación indicada en la expresión (-3) (-12) ?

GaryK [48]

Answer:

Cual es la forma más simple al efectuar la operación indicada en la expresión (-3) (-12) ? this means What is the simplest way to perform the operation indicated in the expression (-3) (-12)?

Step-by-step explanation:

Multiply -3 by -12 and get 36. hope this was helpful.

7 0

3 years ago