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Tema [17]
3 years ago
10

Benzoyl peroxide, the substance most widely used against acne, has a half-life of 9.8 × 103 days when refrigerated. How long wil

l it take to lose 5% of its potency (95% remaining)? Assume that this is a first-order reaction. Give your answer in scientific notation.
Chemistry
1 answer:
prohojiy [21]3 years ago
7 0

Answer:

7.3\times 10^2\ days

Explanation:

Given that:

Half life = 9.8\times 10^3 days

t_{1/2}=\frac{\ln2}{k}

Where, k is rate constant

So,  

k=\frac{\ln2}{t_{1/2}}

k=\frac{\ln2}{9.8\times 10^3}\ days^{-1}

The rate constant, k = 0.00007 days⁻¹

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given:

5 % is lost which means that 0.05 of [A_0] is decomposed. So,

\frac {[A_t]}{[A_0]} = 1 - 0.05 = 0.95

t = ?

\frac {[A_t]}{[A_0]}=e^{-k\times t}

0.95=e^{-0.00007\times t}

t = 732.76 days = 7.3\times 10^2\ days

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Can someone help please.
vovangra [49]
I think that the answer is B
5 0
3 years ago
A galvanic (voltaic) cell consists of an electrode composed of nickel in a 1.0 M nickel(II) ion solution and another electrode c
Andre45 [30]

<u>Answer:</u> The standard potential of the cell is 0.77 V

<u>Explanation:</u>

We know that:

E^o_{Ni^{2+}/Ni}=-0.25V\\E^o_{Cu^{+}/Cu}=0.52V

The substance having highest positive E^o reduction potential will always get reduced and will undergo reduction reaction.

The half reaction follows:

<u>Oxidation half reaction:</u> Ni(s)\rightarrow Ni^{2+}(aq)+2e^-

<u>Reduction half reaction:</u> Cu^{+}(aq)+e^-\rightarrow Cu(s)       ( × 2)

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

Putting values in above equation follows:

E^o_{cell}=0.52-(-0.25)=0.77V

Hence, the standard potential of the cell is 0.77 V

5 0
3 years ago
how many grams of water are produced when 15 grams of magnesium hydroxide are reacted with sulfuric acid​
Mila [183]
<h3>Answer:</h3>

9.26 g of water

<h3>Explanation:</h3>

We are given;

  • 15 grams of magnesium hydroxide;

Required to calculate the mass of water produced;

We will use the following steps;

<h3>Step 1: Write the balanced equation for the reaction</h3>

Magnesium hydroxide reacts with sulfuric acid to produce water and magnesium sulfate;

Therefore, the equation of the reaction is;

Mg(OH)₂(aq) + H₂SO₄(aq) → MgSO₄(aq) + 2H₂O(l)

<h3>Step 2: Determine the number of moles of Mg(OH)₂ used </h3>

Number of moles = Mass ÷ Molar mass

Molar mass of Mg(OH)₂ =58.320 g/mol

Therefore;

Moles of Mg(OH)₂ = 15 g ÷ 58.320 g/mol

                             = 0.257 moles

<h3>Step 3: Calculate the moles of water produced</h3>

From the equation 1 mole of Mg(OH)₂ reacts to produce 2 moles of water;

Therefore; Moles of water = moles of Mg(OH)₂ × 2

Moles of water = 0.257 moles × 2

                         = 0.514 moles

<h3>Step 4: Calculate the mass of water produced;</h3>

Mass = Moles × Molar mass

Molar mass of water = 18.02 g/mol

Therefore;

Mass of water = 0.514 moles × 18.02 g/mol

                        = 9.26 g

Therefore, 9.26 g of water will be produced

3 0
3 years ago
!!please help asap ty!!
Bess [88]

Answer:

2.89× 10²³ atom

Explanation:

Given data:

Number of atoms of Zn = ?

Number of moles of Zn = 0.48 mol

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atom

0.48 mol ×  6.022 × 10²³ atom / 1mol

2.89× 10²³ atom

7 0
3 years ago
Compute the number of grams(g) of lead in 22.5 moles of lead.
iogann1982 [59]

Answer:

4662 in grams

Explanation:

hope this helps :).

7 0
3 years ago
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