Changes in matter occur every day. There are two types of ways matter can be altered; physically and chemically. Physical changes do not change the composition of the matter while chemical changes occur when one or more substances turn into a completely new substance. Physical changes can be seen through an altering of the substances physical property. A substances physical property is observed and measured without changing the composition of the subject. Descriptive words that would help to identify a substance’s physical property include hard, soft, brittle, flexible, heavy, and light just to name a few. Let’s say you’re eating, throughout the day your stomach starts to growl that is what happens when your stomach is digesting your food. Digestion is an example of chemical change. Chemical change happens every day and more than half the time we don’t realize it whether it’s metal starting to rust, or our food starting to rot. Physical change can happen when your popsicle starts to melt, or your water starting starting to boil. These are examples of physical change.
Answer:
Ethanol = 102.29 g
Carbon Dioxide = 97.71 g
Solution:
The Balance Chemical Equation for the fermentation of Glucose is as follow,
C₆H₁₂O₆ → 2 C₂H₅OH + 2 CO₂
Mass of Ethanol produced:
According to equation;
180.156 g (1 mole) C₆H₁₂O₆ produces = 92.14 g (2 moles) of C₂H₅OH
So,
200 g of C₆H₁₂O₆ will produces = X g of C₂H₅OH
Solving for X,
X = (200 g × 92.14 g) ÷ 180.156 g
X = 102.29 g of C₂H₅OH
Mass of Carbon Dioxide produced:
According to equation;
180.156 g (1 mole) C₆H₁₂O₆ produces = 88.02 g (2 moles) of CO₂
So,
200 g of C₆H₁₂O₆ will produces = X g of CO₂
Solving for X,
X = (200 g × 88.02 g) ÷ 180.156 g
X = 97.71 g of CO₂
Answer:
1.2 L
Explanation:
Step 1: Write the balanced equation
Mg + 2 HCl ⇒ MgCl₂ + H₂
Step 2: Calculate the moles corresponding to 2.3 g of Mg
The molar mass of Mg is 24.31 g/mol.
2.3 g × 1 mol/24.31 g = 0.095 mol
Step 3: Calculate the moles of H₂ produced
0.095 mol Mg × 1 mol H₂/1 mol Mg = 0.095 mol H₂
Step 4: Calculate the volume occupied by the hydrogen
We will use the ideal gas equation.
P × V = n × R × T
V = n × R × T/P
V = 0.095 mol × (0.0821 atm.L/mol.K) × 298 K/2 atm = 1.2 L
Answer:
Picture D represents the only possible option as the Picture D rearranges the atoms whereas A, B, and C did not. Option D
Explanation:
We can see in the pictures A, B and C the atoms are not arranged properly if we keep the fundamental image in view. By comparing all the images you will observe how the atoms in the fundamental image are differently represented in image A, B and C. Also the fundamental image have 10 atoms whereas all the option except D varies the number of atoms
1) The question contains an unknown unit
The number 8908.8 has to be in units of mass: for example, kg or grams.
Here you indicated L.
I am going to work assuming that L is a mass unit. So you can see the way to solve the problem, but you have to verifiy the real unit of the statement and substitute with it.
With that in mind you can find the density of the liquid from:
density = mass / volume
2) Calculate the volume.
The volume of the liquid is the volume of the vessel, because it is filled.
The volume of the vessel is calculated from the formula of volume for a rectantular prism.
Volume of a rectangular prism = area of the base * height = side * side * height
=> Volume = 10 dm * 4 dm * 6 dm = 240 dm^3 = 240 liter
3) Calculate the density:
density = mass /volume = 8,908.8 L / 240 liter = 37.12 L / dm^3
Answer: 37.12 L / dm^3