3 years ago

If f(x) = |x - 4| + 5, find f(1)

Mathematics

2 answers:

tia_tia [17]3 years ago

6 0

I believe 8 is the answer

Gemiola [76]3 years ago

3 0

F(1) = |1 - 4| + 5 = !-3) + 5 = 3 + 5 = 8 (answer)

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ki77a [65]

The answer
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3 years ago

6x2y^3/3xy Use Laws of exponents. answer is 2xy^2 but I don't know how to get it. My initial answer was 4y^2

allsm [11]

Step-by-step explanation:

$\frac{6x^{2}y^{3}}{3xy}$

If it helps, write as a product of fractions, grouped by variable.

$\frac{6}{3} \frac{x^{2}}{x} \frac{y^{3}}{y}$

Now reduce using exponent rules.

$2xy^{2}$

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3 years ago

Simplify 12n-2n⁴-10n-2n⁴+n a. 4n⁴+3n b. 3n c. -4n⁴+3n d. -n¹¹

Serjik [45]

The answer is C. -4n⁴+3n.

Separate the expression by its like terms.

12n-2n⁴-10n-2n⁴+n

12n+(-10n)+n=3n

-2n⁴+-2n⁴=-4n⁴

The simplified expression comes out to -4n⁴+3n.

3 0

3 years ago

Read 2 more answers

Please help I’ll give brainiest! Make sure to tell me steps by steps!:D

asambeis [7]

Answer:

see below

Step-by-step explanation:

h(x) = 2x-10

Let x=3

h(3) = 2*3 -10

= 6-10

Let x=-3

h(-3) = 2*-3 -10

= -6-10

=-16

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3 years ago

Parabolas, hyperbolas, ellipses, and circles are all types of __________.

Harman [31]

Parabolas, hyperbolas, ellipses, and circles are all types of (A) roulette's.

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3 years ago