Answer:
1. d
2. c
Step-by-step explanation:
For the first part:
if w is width and length is 2 times that, what would the length be?
For the second part:
we know that the perimeter is less-than 48in, so we can start by saying
something<48
next you have to determine what that something is: the perimeter.
To find perimeter, you add the length of the sides. We already know that there are two sides which measure 'w' units, and two sides which measures are the expression you're finding in the first part. So, you simply need to add these together!
width + width + length + length<48.
(Note: you'll obviously want to replace the words width and length with the values for the width and length; in the case of width, the value is given in the problem in the form of a variable, and the length is the expression you solve for in the first part.
You should be able to solve to find the expression from the first part on your own, and once you have those, simply plug the value of the width and the length into the expression. Rather than just giving you the answer, this allows you to still work it out on your own to a certain extent.
Make sense? (:
Answer:
1. +15
2.-2
Step-by-step explanation:
the meaning of zero in each situation.
What are the values of mode and median in the following set of numbers? 1,3,3,6,6,5,4,3,1,1,2 Mode: 1, 2, Median: 2 Mode: 1,3, M
AURORKA [14]
<h3><u>given</u><u>:</u></h3>
<u>
</u>
<h3><u>to</u><u> </u><u>find</u><u>:</u></h3>
the mode and median of the given numbers set.
<h3><u>solution</u><u>:</u></h3><h3><u>mode</u><u>:</u></h3>
the most frequently occurred number.
<h3><u>median</u><u>:</u></h3>
first arrange all the numbers in either decending or ascending order, then find the number in the middle.
<u>hence</u><u>,</u><u> </u><u>the</u><u> </u><u>median</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>following</u><u> </u><u>data</u><u> </u><u>set</u><u> </u><u>is</u><u> </u><u>3</u><u> </u><u>and</u><u> </u><u>the</u><u> </u><u>mode</u><u> </u><u>is</u><u> </u><u>1</u><u> </u><u>and</u><u> </u><u>3</u>
If the width is 6.5 then double that to work out the two widths which would be 13. Take that from the perimeter so you're left with 21. Half 21 to work out one length which is 10.5. Length = 10.5
