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shtirl [24]
3 years ago
10

What is the least common denominator of the fraction 4 over x plus the fraction 2 x over x minus 1 plus the fraction x plus 3 ov

er 2 x?
2x − 1
2x(x − 1)
2(x − 1)
2(x2 − 1)
Mathematics
1 answer:
Leya [2.2K]3 years ago
8 0

If we consider x having any other value then 0,1 or 2 then the answer is b.2x(x-1)

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Jamal claims that the graph of f(x)+2 is equivalent to the graph of f(x+k). For the case where Jamal claim is correct, what must
rusak2 [61]

Answer:

K=2

Hope this helps

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Scores on a certain intelligence test for children between ages 13 and 15 years are approximately normally distributed with μ=10
Tju [1.3M]

Answer: 0.8238

Step-by-step explanation:

Given : Scores on a certain intelligence test for children between ages 13 and 15 years are approximately normally distributed with \mu=106 and \sigma=15.

Let x denotes the scores on a certain intelligence test for children between ages 13 and 15 years.

Then, the proportion of children aged 13 to 15 years old have scores on this test above 92 will be :-

P(x>92)=1-P(x\leq92)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{92-106}{15})\\\\=1-P(z\leq })\\\\=1-P(z\leq-0.93)=1-(1-P(z\leq0.93))\ \ [\because\ P(Z\leq -z)=1-P(Z\leq z)]\\\\=P(z\leq0.93)=0.8238\ \ [\text{By using z-value table.}]

Hence, the proportion of children aged 13 to 15 years old have scores on this test above 92 = 0.8238

4 0
3 years ago
Help a bab out with something, please?
Nuetrik [128]

Answer:

18

Step-by-step explanation:

8 0
3 years ago
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Which of the following equations will produce the graph shown below?
Korolek [52]
C is the correct answer
8 0
3 years ago
Find the magnitude of WX for W(-2, 8, -3) and X(1, 4, -1)
zheka24 [161]

The magnitude of WX is  \sqrt{29}  ⇒ c

Step-by-step explanation:

The magnitude of XY (its length) where,

  • X=(x_{1},y_{1},z_{1})
  • Y=(x_{2},y_{2},z_{2})

is IXYI = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}+(z_{2}-z_{1})^{2}}

∵ W = (-2 , 8 , -3)

∵ X = (1 , 4 , -1)

- To find the magnitude of WX use the formula above

∴ x_{1} = -2 and x_{2} = 1

∴ y_{1} = 8 and y_{2} = 4

∴ z_{1} = -3 and z_{2] = -1

- Substitute these values in the rule above

∵ IWXI = \sqrt{(1--2)^{2}+(4-8)^{2}+(-1--3)^{2}}=\sqrt{9+16+4}

∴ IWXI = \sqrt{29}

The magnitude of WX is  \sqrt{29}

Learn more:

You can learn more about the position of an object in brainly.com/question/10940255

#LearnwithBrainly

8 0
3 years ago
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