Question

What is the inverse of the function fx=19/x3

Answer 1

$f(x) = \frac{19}{x^3}$

Set f(x) = y and solve for x:

$y = \frac{19}{x^3}$

$\frac{19}{y} = x^3$

$x = \sqrt[3]{\frac{19}{y} }$

Now, switch the x and y:

$y = \sqrt[3]{\frac{19}{x} }$

Now, write it in the correct notation, and your answer is:

$f^{-1}(x) = \sqrt[3]{\frac{19}{x} }$

Hope I could help!