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2 years ago

Find the volume of the cylinder. Express your answer in terms of π.

2 answers:

8 0

<span>Cylinder Volume = </span><span>π <span>• r² • height (or length)
</span></span>
<span>Cylinder Volume = PI * 7^2 * 15
</span>
<span><span>Cylinder Volume = PI * 49 * 15</span>
</span>
Cylinder Volume = <span> <span> <span> 2309.07 OR it equals

PI * 735

answer is "b"

(actually the answer should read 735 * PI cm^3. It is in cubic centimeters and it is NOT PI that is being cubed.)

SOURCE: http://www.1728.org/diamform.htm
</span></span></span>

11Alexandr11 [23.1K]2 years ago

8 0

Answer:

The correct option is b.

Step-by-step explanation:

Given information: Radius of the cylinder r = 7 cm and length or height h is 15 cm.

The volume of a cylinder is

$V=\pi r^2h$

Where, r is the radius and h is height.

Substitute r=7 and h=15 in the above formula.

$V=\pi (7)^2(15)$

$V=\pi\times (7)^2\times (15)$

$V=\pi\times 49\times 15$

$V=\pi\times 735$

$V=735\pi$

The volume of the cylinder is 735π cm³. Therefore the he correct option is b.

You might be interested in

The perimeter of a rectangle is 22cm. the area is 28cm2. what are the lengths of the sides ?

MissTica

Answer: length: 7cm

width:4cm

Step-by-step explanation:

Area: L × W

7×4=28

Perimeter =L±L+W+W

7+7+4+4=22

7 0

3 years ago

If sinA+cosecA=3 find the value of sin2A+cosec2A

Irina18 [472]

Answer:

$\sin 2A + \csc 2A = 2.122$

Step-by-step explanation:

Let $f(A) = \sin A + \csc A$ , we proceed to transform the expression into an equivalent form of sines and cosines by means of the following trigonometrical identity:

$\csc A = \frac{1}{\sin A}$ (1)

$\sin^{2}A +\cos^{2}A = 1$ (2)

Now we perform the operations: $f(A) = 3$

$\sin A + \csc A = 3$

$\sin A + \frac{1}{\sin A} = 3$

$\sin ^{2}A + 1 = 3\cdot \sin A$

$\sin^{2}A -3\cdot \sin A +1 = 0$ (3)

By the quadratic formula, we find the following solutions:

$\sin A_{1} \approx 2.618$ and $\sin A_{2} \approx 0.382$

Since sine is a bounded function between -1 and 1, the only solution that is mathematically reasonable is:

$\sin A \approx 0.382$

By means of inverse trigonometrical function, we get the value associate of the function in sexagesimal degrees:

$A \approx 22.457^{\circ}$

Then, the values of the cosine associated with that angle is:

$\cos A \approx 0.924$

Now, we have that $f(A) = \sin 2A +\csc2A$ , we proceed to transform the expression into an equivalent form with sines and cosines. The following trignometrical identities are used:

$\sin 2A = 2\cdot \sin A\cdot \cos A$ (4)

$\csc 2A = \frac{1}{\sin 2A}$ (5)

$f(A) = \sin 2A + \csc 2A$

$f(A) = \sin 2A + \frac{1}{\sin 2A}$

$f(A) = \frac{\sin^{2} 2A+1}{\sin 2A}$

$f(A) = \frac{4\cdot \sin^{2}A\cdot \cos^{2}A+1}{2\cdot \sin A \cdot \cos A}$

If we know that $\sin A \approx 0.382$ and $\cos A \approx 0.924$ , then the value of the function is:

$f(A) = \frac{4\cdot (0.382)^{2}\cdot (0.924)^{2}+1}{2\cdot (0.382)\cdot (0.924)}$

$f(A) = 2.122$

8 0

3 years ago

*****REALLY NEED IMMEDIATE HELP***<br> (Answer?)

Step2247 [10]

Answer:

eegstecation

Yea YEA

Step-by-step explanation:

8 0

2 years ago

Two forest service watchtowers spot a fire in the distance. The fire is 27 miles from Tower 2. About how far apart are the two w

Reptile [31]

Given that the two watchtowers spotted fire in the distance and watch tower 2 was 27 miles from the fire. Assuming that the fire is in the middle of both watch towers, then the distance between the two watch towers will be given by:
distance=[distance of fire from watch tower 1]+[distance of fire from watch tower 2]
=27+27
=53 miles

8 0

3 years ago

The given measurements may or may not determine a triangle. If not, then state that no triangle is formed. If a triangle is form

Fofino [41]

<h3>Answer:</h3><h3>C = 28.2, A = 25.8, a = 6.5</h3>

See diagram below.

==============================================

Work Shown:

Given info is

B = 126 degrees

b = 12

c = 7

Use the Law of Sines to solve for angle C

sin(C)/c = sin(B)/b

sin(C)/7 = sin(126)/12

sin(C)/7 = 0.067418082864579

sin(C) = 7*0.067418082864579

sin(C) = 0.471926580052053

C = arcsin(0.471926580052053) or C = 180-arcsin(0.471926580052053)

C = 28.1594278560921 or C = 180-28.1594278560921

C = 28.1594278560921 or C = 151.840572143908

C = 28.2 or C = 151.8

We have two possible angle values for C.

-----------------

If C = 28.2, then A = 180-B-C = 180-126-28.2 = 25.8

If C = 151.8, then A = 180-B-C = 180-126-151.8 = -97.8

So it is not possible for C = 151.8 (because it leads to angle A being negative)

Therefore, only C = 28.2 is possible.

-----------------

Use the law of cosines to find the remaining side 'a'

a^2 = b^2 + c^2 - 2*b*c*cos(A)

a^2 = (12)^2 + (7)^2 - 2*(12)*(7)*cos(25.8)

a^2 = 144 + 49 - 168*0.900318771402194

a^2 = 144 + 49 - 151.253553595569

a^2 = 41.7464464044315

a = sqrt(41.7464464044315)

a = 6.46114900032738

a = 6.5

-----------------

Only one triangle is possible

The fully solved triangle has these angles and sides:

A = 25.8 (approx)
B = 126
C = 28.2 (approx)
a = 6.5 (approx)
b = 12
c = 7

With stuff in bold representing the terms we solved for previously. Attached below is an image of the fully solved triangle.

4 0

3 years ago