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Bas_tet [7]
3 years ago
5

*****REALLY NEED IMMEDIATE HELP*** (Answer?)

Mathematics
1 answer:
Step2247 [10]3 years ago
8 0

Answer:

eegstecation

Yea YEA

Step-by-step explanation:

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A moving company’s moving rates can be represented by the function f(x) = 3x + 400, where x is the number of miles for the move.
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Answer:

B) h(x) = –2x + 200

Step-by-step explanation:

f(x) = 3x + 400

g(x) = 5x + 200

f(x) - g(x) = 3x + 400 - (5x + 200) = -2x + 200

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A rectangle or a parallelogram is a polygon with only 2 congruent sides and 2 congruent angles.
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Find the derivative of sinx/1+cosx, using quotient rule​
Mrrafil [7]

Answer:

f'(x) = -1/(1 - Cos(x))

Step-by-step explanation:

The quotient rule for derivation is:

For f(x) = h(x)/k(x)

f'(x) = \frac{h'(x)*k(x) - k'(x)*h(x)}{k^2(x)}

In this case, the function is:

f(x) = Sin(x)/(1 + Cos(x))

Then we have:

h(x) = Sin(x)

h'(x) = Cos(x)

And for the denominator:

k(x) = 1 - Cos(x)

k'(x) = -( -Sin(x)) = Sin(x)

Replacing these in the rule, we get:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2}

Now we can simplify that:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2} = \frac{Cos(x) - Cos^2(x) - Sin^2(x)}{(1 - Cos(x))^2}

And we know that:

cos^2(x) + sin^2(x) = 1

then:

f'(x) = \frac{Cos(x)- 1}{(1 - Cos(x))^2} = - \frac{(1 - Cos(x))}{(1 - Cos(x))^2} = \frac{-1}{1 - Cos(x)}

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Given vectors
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Answer:

option 2, 3, and 5

Step-by-step explanation:

yuh

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