Width would have to be a quadratic
Use long division to find the other factor of the cubic polynomial P (x).
P (x) factors in case it is reducible over R[x]
if it weren't then P (x) mod R [x] would be a field
otherwise you could use the Eisenstein Criterion.
Answer:
42°
Step-by-step explanation:
This is right triangle and sum of 2 angles is 90°:
y+48°=90°
so y= 90°- 48°= 42°
Just finished this for another student.
Length = 9
What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
Answer:
105 shifts
Step-by-step explanation:
Hourly net rate of pay = $12
1 shift = 8 hours
⇒ net pay per shift = $12 × 8 = $96
Total cost = tuition + residence + books
= $4500 + $4800 + $700
= $10,000
To calculate how many shifts Joanne needs to work, divide the total cost by the pay per shift and round it up:
Number of shifts = total cost ÷ net pay per shift
= $10,000 ÷ $96
= 104.1666666...
= 105 shifts
<u>Note</u>: we need to round up, as if Joanne works 104 shifts, she will earn $9,984 which is not quite enough to pay for tuition, residence and books.
