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gregori [183]
4 years ago
6

An object with a mass of 5.6 g raises the level of water in a graduated cylinder from 25.1 mL to 33.9 mL. What is the density of

the object?
Chemistry
2 answers:
kondor19780726 [428]4 years ago
6 0

Answer:

0.6364 g/cm^3

Explanation:

Density = mass/volume

Where mass = 5.6g and...

Volume = (33.9 - 25.1) = 8.8ml

Where 1ml = 1 cm^3

Density = 5.6/8.8 = 0.6364 g/cm^3

monitta4 years ago
5 0

Answer:

0.64 g/cm³

Explanation:

Density is defined as mass divided by volume. The mass of the object we know (5.6 g). In order to find the volume it occupies, we consider the water displaced in the graduated cylinder. The object raised the level of water by the same volume that it occupies. So the volume of the object is then:

(33.9 mL - 25.1 mL) = 8.8 mL

The density of the object is then calculated:

D = m/V = (5.6 g)/(8.8 mL) = 0.64 g/mL = 0.64 g/cm³

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2 years ago
A propane stove burned 470 grams propane and produced 625 grams of water (this is the actual yield) C3H8 +5O2=3CO2+4H20. What wa
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Answer:

81.3%

Explanation:

Step 1:

The balanced equation for the reaction:

This is shown below:

C3H8 + 5O2 —> 3CO2 + 4H2O

Step 2:

Data obtained from the question. This includes:

Mass of propane (C3H8) = 470 g

Actual yield of water (H2O) = 625 g

Percentage yield of water (H2O) =?

Step 3:

Determination of the mass of propane (C3H8) burned and the mass of water (H2O) produce from the balanced equation. This is illustrated below:

C3H8 + 5O2 —> 3CO2 + 4H2O

Molar Mass of C3H8 = (3x12) + (8x1) = 36 + 8 = 44g/mol

Molar Mass of H2O = (2x1) + 16 = 2 + 16 = 18g/mol

Mass of H2O from the balanced equation = 4 x 18 = 72g

From the balanced equation above,

44g of C3H8 was burned and 72g of H2O was produced.

Step 4:

Determination of the theoretical yield of H2O. This is illustrated below:

From the balanced equation above,

44g of C3H8 produced 72g of H2O.

Therefore, 470g of C3H8 will produce = (470x72)/44 = 769.09g of H2O.

Therefore, the theoretical yield of H2O is 769.09g

Step 5:

Determination of the percentage yield of water (H2O). This is illustrated below:

Actual yield of water (H2O) = 625g

theoretical yield of H2O = 769.09g

Percentage yield of water (H2O) =?

Percentage yield = Actual yield/Theoretical yield x100

Percentage yield = 625/769.09 x100

Percentage yield = 81.3%

Therefore, the percentage yield of water (H2O) is 81.3%

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4 years ago
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Answer:

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Explanation:

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