An unknown compound displays singlets at δ 2.1 ppm and 2.56 ppm in the ratio of 3:2. what is the structure of the compound?
1 answer:
1) As can be seen from any 1H NMR chemical shift ppm tables, hydrogens which have δ values from 2ppm to 2.3ppm are hydrogens from carbon which is bonded to a carbonyl group. From this, we can conclude that our hydrogens belong to the type, but from 2 different alkyl groups because of 2 different signals.
2) So, one alkyl group is CH3 and second one can be CH or CH2.
3) If we know that ratio between two types of hydrogens is 3:2, it can be concluded that second alkyl group is CH2.
4) Finally, we don't have any other signals and it indicates that part of the compound which continues on CH2 is exactly the same as the first part.
The ratio remains the same, 3:2 ie 6:4
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Answer:
a. Approximately .
b. Approximately .
Explanation:
The unit of concentration "" is equivalent to "
", which means "moles per liter."
However, the volume of both solutions were given in mililiters . Convert these volumes to liters:
.
.
In a solution of volume where the concentration of a solute is
, there would be
(moles of) formula units of this solute.
Calculate the number of moles of formula units in each of the two solutions:
Solution in a.:
.
Solution in b.:
.
What volume of that (same as
)
solution would contain that many
For the solution in a.:
.
Convert the unit of that volume to milliliters:
.
Similarly, for the solution in b.:
.
Convert the unit of that volume to milliliters:
.