Question

Consider the following generic reaction for which Kp = 5.51 × 105 at 25°C:2R(g)+A(g)⇌2Z(g)What is the value of Kc for the reaction at the same temperature?1.37 × 10^92.25 × 10^41.35 × 10^75.51 × 10^5

Answer 1

Answer:

Kc = 1.35x10^7

Explanation:

Let's write the reaction again:

2R + A <------> 2Z    Kp = 5.51x10^5

In order to know the value of Kc, we need to write the expression that relations the Kp with Kc which is:

Kp = Kc * (RT)^Δn (1)

Where:

R: 0.082 L atm/ K mol

Δn: difference between the coefficients of the reaction

Kc: equilibrium constant

T: temperature in K

Now, from the equation (1) we can solve for Kc:

Kc = Kp / (RT)^Δn (2)

Now, before do any calculations, let's do first the value of Δn:

Δn = 2 - (2+1) = -1

Now, replacing all values in (2):

Kc = 5.51x10^5 / (0.082*298)^-1

Kc = 1.346x10^7

The third option is the correct one.