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Olin [163]
2 years ago
11

Explain how chemists can state with certainty that no one will discover an element that would appear on the periodic table betwe

en sulfur (S) and chlorine (CI)
Chemistry
1 answer:
gayaneshka [121]2 years ago
6 0
Sulfur has 16 protons and chlorine has 17 protons. Since the placement on the periodic table is equal to the number of protons, and also since it is impossible to have an element with a non-whole number of protons, there can be no element between sulfur and chlorine.
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What are the uses of polythene?
Crank
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2 years ago
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What parts of microscope that enlarge the object once seen under the microscope
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Answer:

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3 years ago
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From the lists of available reagents select the one(s) you would use to in a preparation of acetophenone (phenyl methyl ketone)
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Answer:

Step 1) hydrolysis using NaOH/H2O to form benzylalcohol

Step2) oxidation to Carboxylic acid using KMnO4 followed by decarboxylation to form benzene

3) friedel craft acylation using CH3COCl/AlCl3

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The above 3 steps will yield acetophenone from methylbenzoate

3 0
2 years ago
A mixture of gaseous reactants is put into a cylinder, where a chemical reaction tums them into gaseous products. The cylinder h
erastova [34]

Answer:

The reaction is exothermic

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In this case, the system is the reaction vessel while the surrounding is the water bath. We see in the question that 300.1J of heat flows out of the system during the reaction. This is heat lost to the surroundings showing that the reaction is exothermic.

As energy is lost to the surroundings, the temperature of the water bath rises accordingly.

6 0
2 years ago
93.0 mL of O2 gas is collected over water at 0.930 atm and 10.0C what would be the volume of this dry gas at STP
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The  volume  of  the  dry   gas  at     stp  is  calculated as follows

calculate  the  number  on  moles  by use  of   PV =nRT  where  n  is  the number  of  moles

n  is therefore  = Pv/RT
P  = 0.930  atm
R(gas  contant=  0.0821  L.atm/k.mol
V= 93ml  to  liters =  93/1000= 0.093L
T=  10  +  273.15 = 283.15k

n=  (0.930  x0.093)  /(0.0821  x283.15) =  3.  72  x10^-3  moles

At  STp    1  mole  =  22.4L
what about  3.72  x10^-3 moles

by  cross  multiplication

volume =  (3.72  x10^-3)mole  x  22.4L/  1  moles  = 0.083 L   or  83.3 Ml
3 0
3 years ago
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