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r-ruslan [8.4K]
4 years ago
12

Reduce the fraction -20t5u2v3 / 48t7u4v .

Mathematics
1 answer:
kondor19780726 [428]4 years ago
6 0
Deal with the numbers and variables step by step 

-20/48  = -5/12
t5 / t7 = t^-2 = 1 /t2
u^2 / u^4 = u^-2 = 1/u^2
v^3 / v = v^2

so answer is      -5v^2 / 12t^2u^2
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Answer:

The answer is below

Step-by-step explanation:

1)

mean (μ) = 12, SD(σ) = 2.3, sample size (n) = 65

Given that the confidence level (c) = 90% = 0.9

α = 1 - c = 0.1

α/2 = 0.05

The z score of α/2 is the same as the z score of 0.45 (0.5 - 0.05) which is equal to 1.65

The margin of error (E) is given as:

E=Z_{\frac{\alpha}{2} }*\frac{\sigma}{\sqrt{n} } =1.65*\frac{2.3}{\sqrt{65} } =0.47

The confidence interval = μ ± E = 12 ± 0.47 = (11.53, 12.47)

2)

mean (μ) = 23, SD(σ) = 12, sample size (n) = 45

Given that the confidence level (c) = 88% = 0.88

α = 1 - c = 0.12

α/2 = 0.06

The z score of α/2 is the same as the z score of 0.44 (0.5 - 0.06) which is equal to 1.56

The margin of error (E) is given as:

E=Z_{\frac{\alpha}{2} }*\frac{\sigma}{\sqrt{n} } =1.56*\frac{12}{\sqrt{45} } =2.8

The confidence interval = μ ± E = 23 ± 2.8 = (22.2, 25.8)

8 0
3 years ago
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Answer:

Step-by-step explanation:

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Answer:

2 is the answer

Step-by-step explanation:

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