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3 years ago

Subtract these polynomials.

Mathematics

2 answers:

Mandarinka [93]3 years ago

8 0

2x^2 + 4x + 3 – 4x^2 +2x +3 = -2x² +6x +6
Answer D

AveGali [126]3 years ago

4 0

Answer: The correct option is

(D) $-2x^2+6x+6.$

Step-by-step explanation: We are given to subtract the following polynomials :

$P=(2x^2+4x+3)-(4x^2-2x-3)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

To subtract the given polynomials, we need to subtract the coefficients of the terms with same powers of the unknown variable x.

From (i), we get

$P\\\\=(2x^2+4x+3)-(4x^2-2x-3)\\\\=2x^2+4x+3-4x^2+2x+3\\\\=(2-4)x^2+(4+2)x+(3+3)\\\\=-2x^2+6x+6.$

Thus, the required resulting polynomial is $-2x^2+6x+6.$

Option (D) is CORRECT.

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3 years ago

Pleaseeee answer quick WILLL GIVE BRAINLIEST!!!!!! Given the expression: 5x10 − 80x2 Part A: Rewrite the expression by factoring

sladkih [1.3K]

Answer:

$5\,x^{10}-80\,x^2=5\,x^2\,(x^4+4)(x^2-2)(x^2+2)$

Step-by-step explanation:

First, extract the greatest common factor of the numerical as well as the variable parts:

the GCF of 5 and 80 is "5", and the GCF between $x^{10}$ and $x^2$ is $x^2$ , then:

$5\,x^{10}-80\,x^2=5\,x^2\,(x^8-16)$

Now, we can re-write the binomial in parenthesis as a difference o squares to be able to factor out even further:

$x^8-16=(x^4)^2-4^2=(x^4-4)(x^4+4)$

we now repeat the process for the binomial difference:

$(x^4-4)=((x^2)^2-2^2)=(x^2-2)(x^2+2)$

So finally the complete factorization is:

$5\,x^{10}-80\,x^2=5\,x^2\,(x^4+4)(x^2-2)(x^2+2)$

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4 years ago