All categories

3 years ago

Subtract these polynomials.

Mathematics

2 answers:

Mandarinka [93]3 years ago

8 0

2x^2 + 4x + 3 – 4x^2 +2x +3 = -2x² +6x +6
Answer D

AveGali [126]3 years ago

4 0

Answer: The correct option is

(D) $-2x^2+6x+6.$

Step-by-step explanation: We are given to subtract the following polynomials :

$P=(2x^2+4x+3)-(4x^2-2x-3)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

To subtract the given polynomials, we need to subtract the coefficients of the terms with same powers of the unknown variable x.

From (i), we get

$P\\\\=(2x^2+4x+3)-(4x^2-2x-3)\\\\=2x^2+4x+3-4x^2+2x+3\\\\=(2-4)x^2+(4+2)x+(3+3)\\\\=-2x^2+6x+6.$

Thus, the required resulting polynomial is $-2x^2+6x+6.$

Option (D) is CORRECT.

You might be interested in

The double-bar graph shows the win-loss records for the Carolina Panthers football team in the years 1995-2001. A bar graph titl

lina2011 [118]

Answer:

the answer is A

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Mathematically verify the outlier(s) in the data set using the 1.5 rule.

statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

$Q_1=\dfrac{11+13}{2}$

$Q_1=\dfrac{24}{2}$

$Q_1=12$

And

$Q_3=\dfrac{16+16}{2}$

$Q_3=\dfrac{32}{2}$

$Q_3=16$

The interquartile range is:

$IQR=Q_3-Q_1$

$IQR=16-12$

$IQR=4$

The data values lies outside the interval $[Q_1-1.5IQR,Q_3+1.5IQR]$ are known as outliers.

$[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]$

$[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]$

$[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]$

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

3 0

3 years ago

The ratio of students to adults on a field trip is 8 to 1. Which table correctly shows this ratio for each grade?

elena-14-01-66 [18.8K]

Answer:

The table C correctly shows the ratio 8:1 for each grade

Step-by-step explanation:

Let

x ----> the number of students

y ----> the number of adults

we know that

$\frac{x}{y}=\frac{8}{1}$

Verify each table

Table A

grade 6

$\frac{96}{88}=\frac{8}{1}$

Multiply in cross

$96(1)=8(88)$ ----> is not true

Table B

grade 6

$\frac{96}{104}=\frac{8}{1}$

Multiply in cross

$96(1)=8(104)$ ----> is not true

Table C

grade 6

\frac{96}{12}=\frac{8}{1}

Multiply in cross

$96(1)=8(12)$

$96=96$ ----> is true

grade 7

$\frac{120}{15}=\frac{8}{1}$

Multiply in cross

$120(1)=8(15)$

$120=120$ ----> is true

grade 8

\frac{136}{17}=\frac{8}{1}

Multiply in cross

$136(1)=8(17)$

$136=136$ ----> is true

therefore

The table C correctly shows the ratio 8:1 for each grade

Table D

grade 6

$\frac{96}{11}=\frac{8}{1}$

Multiply in cross

$96(1)=8(11)$ ----> is not true

3 0

3 years ago

Read 2 more answers

What are the x- and y- intercepts of -x + 4y = 8?

Oksana_A [137]

Answer:

X intercept: -8

Y intercept: 2

Step-by-step explanation:

Simplify the equation, and then solve like a normal two-step equation. (I'm sorry that it wasn't a great explanation. If you want a better one just send me an email in the inbox and I can give you a better explanation.)

8 0

3 years ago

Read 2 more answers

Help pls!!!!!!!!!!!!!!

Sholpan [36]

Answer:

46°

Step-by-step explanation:

tan Ф = 21/20

Ф = tan-1 (21/20)

= 46°

8 0

3 years ago