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PIT_PIT [208]
3 years ago
8

The product of x and 2 is less than or equal to 4

Mathematics
1 answer:
MissTica3 years ago
5 0
2x≤4

I'm not sure how else to help you in this situation, without you providing me with more information.  If you want the solution for x, you would just divide both sides by the coefficient of the variable, or 2, resulting in the inequality:

x ≤ 2

Hope this helps! Comment if you need to add info or have any more questions about this problem.
You might be interested in
Find the 8th term of the geometric sequence 3, 9, 27, ...
miv72 [106K]

Answer:

8th term- 6,561

Step-by-step explanation:

Each term in the sequence is being multiplied by 3. For example, 3x3=9 and 9x3=27. Now, we need to continue multiplying numbers, so we can list them all here, still starting with 3.

1&2) 3x3=9

3) 9x3=27

4) 27x3=81

5) 81x3=243

6) 243x3=729

7) 729x3=2,187

8) 2,187x3=6,561

The 8th term of the geometric sequence is 6,561.

Hope this helps and have a great day! ^^

3 0
2 years ago
Jordan wants to buy a tuna sandwich. The price of a tuna sandwich combo is $7.20. If he wants just the tuna sandwich, the cost i
pickupchik [31]

Answer:

$16.91

Step-by-step explanation:

7 0
3 years ago
Help find DC Please
Ymorist [56]

Answer:

Step-by-step explanation:

3 0
2 years ago
Each of three coins has two sides, heads and tails. Represent the heads or tails status of each coin by a logical variable (A fo
jeka94

Answer:

(a) F(A, B, C) = AB'C' + A'BC' + A'B'C

(b) F(A, B, C) = (A' + B' + C')(A' + B + C)(A + B' + C)(A + B + C')(A + B + C)

Step-by-step explanation:

(a) If F(A, B, C) = 1 iff exactly one of the coins is heads, then either

A is heads and the others are tails (AB'C')

B is heads and the others are tails (A'BC')

C is heads and the others are tails (A'B'C)

Hence, as a minterm expansion,

F(A, B, C) = AB'C' + A'BC' + A'B'C

(b) To get the corresponding maxterm expansion, we convert to binary.

F(A, B, C) = \sum (100, 010, 001) = \sum(4,2,1)

The maxterm is the product of the complements.

F(A, B, C) = \prod (0, 3, 5, 6, 7) = \prod(000, 011, 101, 110, 111)

Expanding,

F(A, B, C) = (A' + B' + C')(A' + B + C)(A + B' + C)(A + B + C')(A + B + C)

3 0
3 years ago
I need this fast thank you! :)
Alex Ar [27]

Answer:

C

Step-by-step explanation:

Hope this helps! Good Luck!

3 0
3 years ago
Read 2 more answers
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