Answer:
6x+3y-15
Step-by-step explanation:
take the x's add them up. take the y put it after the answer of the x's then subtract the y. (im just waffling)
Surface area is the area of the faces added together.
First lets find the area of one of the triangles.
Area of triangle is 1/2*base*hight
Area=1/2*2*3= 3
Area of ONE tringle is 3, and area of the FOUR tringles is 4*3 whihc is 12
Now lets find area of square
area of square is side*side
So, area is 2*2 which is 4
Now lets add area of triangles+area of square
12+4 which 16
Surface area is 16
The first 5 is in the 10s place. The second is in the ones. To write this out, it would be 5 tens (50), plus 5 ones (5); 55. I don't know if this is what you were looking for, but I hope I could help in some way!
Hello i am new here how are you doing
Answer:
The sum of all exterior angles of BEGC is equal to 360° ⇒ answer F only
Step-by-step explanation:
* Lets revise some facts about the quadrilateral
- Quadrilateral is a polygon of 4 sides
- The sum of measures of the interior angles of any quadrilateral is 360°
- The sum of measures of the exterior angles of any quadrilateral is 360°
* Lets solve the problem
- DEGC is a quadrilateral
∵ m∠BEG = (19x + 3)°
∵ m∠EGC = (m∠GCB + 4x)°
∵ The sum of the measures of its interior angles is 360°
∴ m∠BEG + m∠EGC + m∠GCB + m∠CBE = 360
∴ (19x + 3) + (m∠GCB + 4x) + m∠GCB + m∠CBE = 360 ⇒ add the like terms
∴ (19x + 4x) + (m∠GCB + m∠GCB) + m∠CBE + 3 = 360 ⇒ -3 from both sides
∴ 23x + 2m∠GCB + m∠CBE = 375
∵ The sum of measures of the exterior angles of any quadrilateral is 360°
∴ The statement in answer F is only true
