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3 years ago

Which expression is equivalent to 9p-3p +2

Mathematics

1 answer:

Dafna1 [17]3 years ago

5 0

You have the right answer 6p+2

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Write the fraction or mixed number as a percent.<br><br> 1 12/25

atroni [7]

Answer:

37/25= 148%

Step-by-step explanation:

make it a mixed fraction the a percentage

6 0

3 years ago

A) La autopista 10 en Haradh, Arabia Saudita, tiene más de 200

xxMikexx [17]

Explicación paso a paso:

Como no dijimos qué calcular, también podemos encontrar el tiempo que tarda el automóvil en viajar por la carretera.

Velocidad = Distancia / Tiempo

Tiempo = Distancia / Velocidad

Dado

Distancia = 200 km

Velocidad = 120 km / h

Sustituir

Tiempo = 200/120

Tiempo = 20/12

Tiempo = 1,67 horas

Por tanto, el tiempo que tarda el coche en recorrer la carretera es de 1,67 horas.

4 0

3 years ago

What is the inverse of the square function?

Elza [17]

Step-by-step explanation:

Square and Square Root (continued)

of each other about the diagonal y=x.Note:when we restrict the domain to x< 0 (less than or equal to 0) the inverse is then f1(x) -

7 0

3 years ago

Cos (0) = square root 2/2 and 3pi/2<0<2 pi , evaluate sin(0) and tan (0)

katovenus [111]

Answer:

$\sin\theta=-\frac{\sqrt2}{2}}$ and $\tan\theta=-1$

Step-by-step explanation:

Given : $\cos\theta=\frac{\sqrt2}{2}$ and $\frac{3\pi}{2}$

To find : Evaluate $\sin\theta$ and $\tan\theta$ ?

Solution :

As $\frac{3\pi}{2}$ means $\theta$ belong to the third or fourth quadrant .

So, $\sin\theta$ is negative and $\tan\theta$ is positive in third and negative in fourth.

Using the formula of trigonometric,

$\sin^2\theta+\cos^2\theta=1$

$\sin\theta=\sqrt{1-\cos^2\theta}$

Substitute $\cos\theta=\frac{\sqrt2}{2}$ ,

$\sin\theta=\pm\sqrt{1-(\frac{\sqrt2}{2})^2}$

$\sin\theta=\pm\sqrt{1-\frac{2}{4}}$

$\sin\theta=\pm\sqrt{1-\frac{1}{2}}$

$\sin\theta=\pm\sqrt{\frac{1}{2}}$

$\sin\theta=-\frac{\sqrt2}{2}}$

Now using another formula,

$\tan\theta=\frac{\sin\theta}{\cos\theta}$

$\tan\theta=\frac{-\frac{\sqrt2}{2}}{\frac{\sqrt2}{2}}$

$\tan\theta=-1$

Therefore, $\sin\theta=-\frac{\sqrt2}{2}}$ and $\tan\theta=-1$ .

7 0

3 years ago

At 5:00 a.m., the temperature outside was 6°F below zero. By 12:00p.m., it rose by 9°F. At 7:00 p.m., the temperature

FinnZ [79.3K]

Answer:

-2 degrees Fahrenheit

Step-by-step explanation:

math also I'm asian

4 0

3 years ago