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kirill [66]
3 years ago
11

What is this expression 2(5x-1)+14

Mathematics
2 answers:
baherus [9]3 years ago
7 0
Greetings!

I'm going to assume you want to simplify the expression: 
2(5x-1)+14

First, distribute the parenthesis:
=2(5x-1)+14

=[(5x)(2)-(1)(2)]+14

=(10x-2)+14

Next, you want to combine like terms:
=(10x-2)+14

=10x+12

This is the furthest the expression can be simplified:
\boxed{10x+12}

I hope this helped!
-Benjamin 
SVETLANKA909090 [29]3 years ago
5 0
Hello there!

Your question states: What is this expression 2(5x-1)+14


2 * 5x = 10x

2 * -1 = -2

10x + -2 + 14 = 10x + 12

Your answer is 10x + 12 


Hope I helped!

Let me know if you need anything else!

~ Zoe
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What is the volume of a right circular cylinder with a radius of 5cm and a height of 12cm?
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Step-by-step explanation:

1. To solve this problem you must use the following formula for calculate the volume of a right circular cylinder, which is shown below:

V=\pi*r^{2}*h

Where r is the radius and h is the height.

2. Now, you must substitute the values given in the problem. Therefore, you obtain the following result:

V=\pi*(5cm)^{2}*(12cm)

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Help! What’s the y intercept of the linear equation 7+y=4.3x
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Step-by-step explanation:

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simplify

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Solve the equation below <br> 9 = x/18 <br> x=<br> What is X?
dedylja [7]
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7 0
2 years ago
Suppose the test scores for a college entrance exam are normally distributed with a mean of 450 and a s. d. of 100. a. What is t
svet-max [94.6K]

Answer:

a) 68.26% probability that a student scores between 350 and 550

b) A score of 638(or higher).

c) The 60th percentile of test scores is 475.3.

d) The middle 30% of the test scores is between 411.5 and 488.5.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 450, \sigma = 100

a. What is the probability that a student scores between 350 and 550?

This is the pvalue of Z when X = 550 subtracted by the pvalue of Z when X = 350. So

X = 550

Z = \frac{X - \mu}{\sigma}

Z = \frac{550 - 450}{100}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 350

Z = \frac{X - \mu}{\sigma}

Z = \frac{350 - 450}{100}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

68.26% probability that a student scores between 350 and 550

b. If the upper 3% scholarship, what score must a student receive to get a scholarship?

100 - 3 = 97th percentile, which is X when Z has a pvalue of 0.97. So it is X when Z = 1.88

Z = \frac{X - \mu}{\sigma}

1.88 = \frac{X - 450}{100}

X - 450 = 1.88*100

X = 638

A score of 638(or higher).

c. Find the 60th percentile of the test scores.

X when Z has a pvalue of 0.60. So it is X when Z = 0.253

Z = \frac{X - \mu}{\sigma}

0.253 = \frac{X - 450}{100}

X - 450 = 0.253*100

X = 475.3

The 60th percentile of test scores is 475.3.

d. Find the middle 30% of the test scores.

50 - (30/2) = 35th percentile

50 + (30/2) = 65th percentile.

35th percentile:

X when Z has a pvalue of 0.35. So X when Z = -0.385.

Z = \frac{X - \mu}{\sigma}

-0.385 = \frac{X - 450}{100}

X - 450 = -0.385*100

X = 411.5

65th percentile:

X when Z has a pvalue of 0.35. So X when Z = 0.385.

Z = \frac{X - \mu}{\sigma}

0.385 = \frac{X - 450}{100}

X - 450 = 0.385*100

X = 488.5

The middle 30% of the test scores is between 411.5 and 488.5.

7 0
3 years ago
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