2r + 2r + 5 + r + 4r - 3 = 38
9r + 5 - 3 = 38
9r + 2 = 38
9r = 38 - 2
9r = 36
9r/9 = 36/9
r = 4cm
Done!
First, simplify the expression
Here you have three terms with
group them in the following way:


Then substitute s=-3 and t=5:

Answer: 19.
Answer:
1={5 and 3} 2={0} 3={0.209 and 4.791} 4={-3 and 4} 5={1 and 9} 6={-4.303 and -0.697}
Step-by-step explanation:
Your probably confused on what a, b, and c means.
The problems are written like this.

That formula finds the zeros.
For example 1:

Then use the formula

If plus then 5, if minus then 3
CHECK:

Hope this helps you understand how to do this by yourself. Now to do the rest ;-;