The answer to your question is this:
Answer:
y=1/3x+2
Step-by-step explanation:
Answer:
{x ∈ R: x<6}
Step-by-step explanation:
Given
- x is a real number
- x is less than 6
Required
Write the set using set builder notation
The very first thing to do is to list out the range of x, using inequalities;
x is less than 6 implies that -infiniti < x < 6
The next step is to translate this to set builder. This is done as follows
x ∈ R - > This means that x is a real number
x < 6 -> where x is less than 6.
Bringing these two together, it gives:
{x ∈ R: x<6}
Hence, the set of real numbers x less than 6 is equivalent to {x ∈ R: x<6} using set builder notation
<h3>
Answers:</h3>
The first ordered pair is ( -4 , -3 )
The second ordered pair is ( 8, 3 )
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Explanation:
The first point is (x,-3) where x is unknown. It pairs up with y = -3 so we can use algebra to find x
x-2y = 2
x-2(-3) = 2 ... replace every y with -3; isolate x
x+6 = 2
x = 2-6
x = -4
The first point is (-4, -3)
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We'll do something similar for the other point. This time we know x but don't know y. Plug x = 8 into the equation and solve for y
x-2y = 2
8-2y = 2
-2y = 2-8
-2y = -6
y = -6/(-2)
y = 3
The second point is (8, 3)
