To solve, we will follow the steps below:
3x+y=11 --------------------------(1)
5x-y=21 ------------------------------(2)
since y have the same coefficient, we can eliminate it directly by adding equation (1) and (2)
adding equation (1) and (2) will result;
8x =32
divide both-side of the equation by 8
x = 4
We move on to eliminate x and then solve for y
To eliminate x, we have to make sure the coefficient of the two equations are the same.
We can achieve this by multiplying through equation (1) by 5 and equation (2) by 3
The result will be;
15x + 5y = 55 ----------------------------(3)
15x - 3y =63 --------------------------------(4)
subtract equation (4) from equation(3)
8y = -8
divide both-side of the equation by 8
y = -1
15x + 28y = 116
x + y = 6
that would be ur system of equations
Answer:
if you are solving for z it is:
Step-by-step explanation:
z=0,-2,1
Answer:
Step-by-step explanation:
Answer is in below attachment
Answer:
6x+4
Step-by-step explanation:
First thing to do is distribute 1/4 into the parenthesis. So 1/4 times 8x and 16. Which will give you 2x and 4. Then add like terms which will be 2x + 4x which is 6x. Then you have the 4 left over so your new equation is 6x+4.