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Radda [10]
3 years ago
13

What is a drawback of getting college credit in high school?

Mathematics
2 answers:
Elina [12.6K]3 years ago
6 0

Answer:

im confused

Step-by-step explanation:

andriy [413]3 years ago
3 0

Answer:

Step-by-step explanation:

We are to highlight the drawbacks of getting college credit in high school.

Whenever college credit is also desired while doing high school,

the student has to make his own arrangement for conveyance to attend both school and college.  Also time constraint to prepare for both exams make student frustrated, out of focus, etc.

All students may not be able to balance two places of education simultaneously.  Though cost may be less compared to separately doing, the problem is sometimes the desired colleges may not be near the student's locality.

Also some private colleges do not recognize school credit and hence not ready to admit the students till they complete fully high school

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laiz [17]
4x + 1 = -3

"The product" is the term used to describe the answer of a multiplication equation.
"increased by" means you're adding.
"a number" refers to a variable.
7 0
3 years ago
Can you help me please.
Kamila [148]

9514 1404 393

Answer:

  a.  (-1/2, 5)

Step-by-step explanation:

The coefficients of x have opposite signs, so the x-terms can be eliminated by adding the two equations.

  (2y -12x) +(3y +12x) = (16) +(9)

  5y = 25 . . . . . . simplify

  y = 5 . . . . . . . . .divide by 5

This matches only answer choice A.

__

<em>Check</em>

The other part of answer choice A is x = -1/2. We can test this to make sure it works:

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5 0
3 years ago
Can someone please help!?
bogdanovich [222]

Answer:

II

Step-by-step explanation

hope that helped

7 0
3 years ago
In ΔRST, r = 52 cm, s = 55 cm and ∠T=48°. Find the length of t, to the nearest centimeter.
quester [9]

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6 0
3 years ago
Tan inverse X + tan inverse Y + tan inverse z=pie prove that X+Y+Z=xyz<br>​
vfiekz [6]

Answer:

see explanation

Step-by-step explanation:

Given

tan^{-1}x + tan^{-1}y + tan^{-1} z = π

let

tan^{-1}x = A , tan^{-1}y = B , tan^{-1}z = C , so

x = tanA, y = tanB , z = tanC

Substituting values

A + B + C = π  ( subtract C from both sides )

A + B = π - C ( take tan of both sides )

tan(A + B) = tan(π - C) = - tanC ( expand left side using addition identity for tan )

\frac{tanA+tanB}{1-tanAtanB} = - tanC ( multiply both sides by 1 - tanAtanB )

tanA + tanB = - tanC( 1 - tanAtanB) ← distribute

tanA+ tanB = - tanC + tanAtanBtanC ( add tanC to both sides )

tanA + tanB + tanC = tanAtanBtanC , that is

x + y + z = xyz

3 0
3 years ago
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