1) local shopping mall
This is most relevant to spending habits. This would be where people would be spending money on a lot of different things and where their spending habits would show. It'd make the most sense to survey people there.
Answer:
The claim that less than 50% of internet users get their health questions answered online is correct, given that according to the survey, 45.98% of people do.
Step-by-step explanation:
Since an online health and medicine company claims that about 50% of Internet users would go to an online sight first for information regarding health and medicine, and a random sample of 1318 Internet users was asked where they will go for information the next time they need information about health or medicine; 606 said that they would use the Internet, to test the claim that less than 50% of Internet users get their health questions answered online, the following calculation must be performed:
1318 = 100
606 = X
606 x 100/1318 = X
60600/1318 = X
45.978 = X
Therefore, the claim that less than 50% of internet users get their health questions answered online is correct, given that according to the survey, 45.98% of people do.
Answer:
On average, they travel 145 miles in a day
Step-by-step explanation:
2,320 ÷ 16 = 145
Answer:
The 95% confidence interval for the population mean span of boys from participating schools in Canada is between 154.3 cm and 160.3 cm.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 100 - 1 = 99
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 99 degrees of freedom(y-axis) and a confidence level of
. So we have T = 1.9842
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 157.3 - 3 = 154.3 cm
The upper end of the interval is the sample mean added to M. So it is 157.3 + 3 = 160.3 cm.
The 95% confidence interval for the population mean span of boys from participating schools in Canada is between 154.3 cm and 160.3 cm.