Please answer correctly!! I’ll mark as brainliest! No links no fake answers

Find the value of x. I WILL GIVE YOU BRAINLIEST!!!!

Elan Coil [88]

Hi there!

$\large\boxed{x = 40}$

We can solve for x knowing that the sum of interior angles in a triangle is 180°.

The square at the bottom indicates a right angle, or 90°. Therefore:

180 = 90 + x + (x + 10)

Combine like terms:

180 = 100 + 2x

Subtract 100 from both sides:

180 - 100 = 2x

80 = 2x

Divide both sides by 2:

x = 40.

5 0

3 years ago

Read 2 more answers

Questions 6-9 Math 8

arlik [135]

6) a
7) a
8) d
9) d

If you want more explanation I'm more than happy to and I hope this helps:)

3 0

3 years ago

Jena's income is $1600 a month, and she plans to budget 1/3 of her income for rent and 1/8 of her income for groceries. Step 2 o

WARRIOR [948]

Answer:

Jena spends $ 733. 33 on her rent and groceries altogether per month.

Step-by-step explanation:

Jena's total income in a month= $1600

Here , expenditure on rent = (1/3) of her income

So, now one- third of her income $1600 is

= $\frac{1}{3} \times 1600 = 533.33$

or, (1/3) of her salary is $533. 33

Hence, Jena spends $ 533. 33 on her rent monthly.

Now, her expenditure on groceries = (1/8) of her income

So, now one- eighth of her income $1600 is

= $\frac{1}{8} \times 1600 = 200$

or, (1/8) of her salary is $ 200.

Jena spends $ 200. on her groceries monthly.

So, Total expenditure = Expenditure on rent + Expenditure on groceries

= $533. 33 + $200 = $733.33

Hence, Jena spends $ 733. 33 on her rent and groceries altogether per month.

7 0

3 years ago

Researchers interviewed street prostitutes in Canada and the United States. The mean age of the 100 Canadian prostitutes upon en

levacccp [35]

Answer:

Step-by-step explanation:

The null and the alternative hypothesis is:

$H_o: \mu_c \ge \mu_{us}$

$H_a : \mu_c < \mu_{us}$

The t- student test statistics can be computed as:

$t = \dfrac{x_c- x_{us}}{\sqrt{\dfrac{\sigma_c^2}{n_c} + \dfrac{\sigma_{us}^2}{n_{us}} }}$

$t = \dfrac{19- 21}{\sqrt{\dfrac{7^2}{100} + \dfrac{8^2}{130} }}$

t = -2.017

degree of freedom = (n₁ - 1) + (n₂ - 1)

= (100 - 1) + (130 - 1)

= 228

Using the data of t-value and degree of freedom;

The P-value = -0.224

Decision rule: Do not reject the null hypothesis if the p-value is greater than ∝(0.01)

Conclusion: We reject the null hypothesis since the p-value is less than ∝.

Therefore, there is enough evidence to conclude that the mean age of entering prostitution in Canada is lower than that of the United States.

5 0

3 years ago

The equation C = 20n + 35 represents the relationship between the cost of school volleyball uniforms, C, in dollars, and the num

Margaret [11]

The equation represent a linear relation with the y-intercept

representing the amount of initial fee.

Correct response:

1. 28 volleyball uniforms

2. Price per uniform

3. Initial flat order fee

4. 10 fewer volleyball uniform

<h3>Methods used for finding the above values</h3>

The given equation that represents the relationship between the cost of school volleyball uniform is; C = 20·n + 35

Where;

C = The uniform costs

n = The number of volleyball uniform ordered

The maximum amount the school has to spend = $600

1. The number of uniforms the school can buy is given by setting C = 600 as follows;

C = 20·n + 35

Therefore;

600 = 20·n + 35

20·n = 600 - 35 = 565

$n = \dfrac{565}{20} = \mathbf{28.25}$

Rounding down to the nearest whole number, we have;

The number of uniforms the school can buy, n = 28 volleyball uniforms.

2. The number 20 represent the additional cost for each extra uniform, which is the unit cost therefore;

20 represents a $20 price per uniform.

3. The 35 in the equation represents an initial flat fee, such as an

ordering or initial fee, which is fixed.

Therefore;

The number 35 represent the fixed cost for producing the uniforms

4. The price per uniform of $30 changes the coefficient of n from 20 to 30 as follows;

C = 30·n + 35

The number of uniforms the school can by with $600 is therefore;

$n = \dfrac{600 - 35}{30} = \mathbf{18.8 \overline 3}$

Which gives;

The number of uniforms the school can purchase at $30 per uniform is n = 18 volleyball uniforms

The difference in the number of uniforms purchased = 28 - 18 = 10

Therefore;

The school can purchase 10 fewer uniforms at $30 per uniform

Learn more about linear equations here:

brainly.com/question/10452752

4 0

2 years ago