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nekit [7.7K]
3 years ago
12

How to do quadratics

Mathematics
1 answer:
larisa [96]3 years ago
6 0
First, put your polynomial in standard form(ax²+bx+c=0). Then plug the a,b and c for x=(-b+-√b²-4ac)÷2a. As a result, you can either get one, two or no real answers.
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What numbers rounded to 200,000 when rounded to the nearest hundred thousand
Elanso [62]

Answer:

The answer would be 150,000 to 249,999

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4 years ago
Use the following situation to complete the problems. The Sno-Cone Shop has a choice of small and large sizes. This week's flavo
xxTIMURxx [149]

Answer:

оататал по стаж вождения ядовитость

Step-by-step explanation:

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6 0
3 years ago
If the perimeter of this triangle is to be no more than 77 feet, write an inequality and
Sergio039 [100]

Given:

Consider the sides of the triangle are 4x+10, 2x-5 and 18 (in feet).

Perimeter of this triangle is to be no more than 77 feet.

To find:

The inequality and solution of the inequality.

Solution:

Perimeter of a triangle is the sum of all side.

Perimeter of given triangle =(4x+10)+(2x-5)+18

Perimeter of this triangle is to be no more than 77 feet. It means perimeter must be less than or equal to 77.

(4x+10)+(2x-5)+18\leq 77

(4x+2x)+(10-5+18)\leq 77

6x+23\leq 77

6x\leq 77-23

6x\leq 54

Divide both sides by 6.

x\leq \dfrac{54}{6}

x\leq 9

Therefore, the required inequality is (4x+10)+(2x-5)+18\leq 77 and the solution is x\leq 9.

8 0
3 years ago
Please help.........
Katyanochek1 [597]

Answer:

a

Step-by-step explanation:

5 0
3 years ago
Find the flux of f = x3 i y3 j z3 k out of the closed surface z = x2 y2 , 0 ≤ z ≤ 5 oriented outward. g
borishaifa [10]

The flux of the given function f = x³i + y³j + z³k is given by f',

f' = 3(x²i + y²j + z²k)

Given, f = x³i + y³j + z³k

we have to find the flux of the given function f = x³i + y³j + z³k

On partial differentiating the function, we get

f' = 3x²i + 3y²j + 3z²k

f' = 3(x²i + y²j + z²k)

So, the flux of the given function f = x³i + y³j + z³k is given by f',

f' = 3(x²i + y²j + z²k)

Hence, the flux of the given function f = x³i + y³j + z³k is given by f',

f' = 3(x²i + y²j + z²k)

Learn more about Vector Calculus here brainly.com/question/10164701

#SPJ4

6 0
2 years ago
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