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DochEvi [55]
3 years ago
15

Divide 40x/ 64y by 5x/ 8y A. 1 B. 3/4 C. 25x^2/ 64y^2 D. 25/64

Mathematics
2 answers:
CaHeK987 [17]3 years ago
6 0
40x/64y / 5x/8y
K C F
40x/64y * 8y/5x

320xy / 320xy

1 <---------- answer
Mademuasel [1]3 years ago
5 0
(40x/64y)/(5x/8y)

(40x/64y)(8y/5x)

320xy/(320xy)

1
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Show how to use known facts to find 6 x 9. Explain how you chose the facts you did
vesna_86 [32]
6
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54. or u can do 6×9 =54 so u can do it either way or do the 9 trick



and the fact is
8 0
3 years ago
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Hi, I need help.
slavikrds [6]

Answer:

B, 24 (second answer choice)

Step-by-step explanation:

4r+7s=23

r-2s=17

8r+14s=46

7r-14s=119

15r=165

r=11

11-2s=17..........by putting value of r in ii

-2s=17-11

2s= -6

s= -3

3r+3s=3*11+3(-3) you get this by putting values of r and s

       =33-9

       =24    (B)

7 0
2 years ago
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Help me please!!! And thank you!!!!
katen-ka-za [31]
<h2>Answer:</h2>

The last answer - 9x squared y squared

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8 0
2 years ago
The table represents a linear function.<br> What is the slope of the function?
TEA [102]

Answer:

-4

Step-by-step explanation:

The function is linear; therefore, the slope of the line joining any two points is the same.

We take any two points from the table and compute the slope or  rise/ run between them— let is take points (-4, -2) and (-2, -10).

The slope m of the line joining the points is

m=\dfrac{\Delta y }{\Delta x } =\dfrac{-2-(-10)}{-4-(-2)} \\\\\boxed{m=-4}

The slope of the function is -4.

3 0
2 years ago
Given the matrices: 1 2 A= 1 -1 2 1 1 B= 3 4 Calculate AB: C11 C12 [2.1] х 1 2 3 4 C21 C22 C11 = C12 = -2 C22 - C215 DONE​
eduard

Answer:

\:c_{11}=-2,\:\:\:c_{12}=-2

\:c_{21}=5,\:\:\:c_{22}=8

Step-by-step explanation:

Given the matrices

A=\begin{pmatrix}1&-1\\ 2&1\end{pmatrix}

B=\begin{pmatrix}1&2\\ \:3&4\end{pmatrix}

Calculating AB:

\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}

Multiply the rows of the first matrix by the columns of the second matrix

                                   =\begin{pmatrix}1\cdot \:1+\left(-1\right)\cdot \:3&1\cdot \:2+\left(-1\right)\cdot \:4\\ 2\cdot \:1+1\cdot \:3&2\cdot \:2+1\cdot \:4\end{pmatrix}

                                   =\begin{pmatrix}-2&-2\\ 5&8\end{pmatrix}

Hence,

\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}=\begin{pmatrix}-2&-2\\ \:5&8\end{pmatrix}

Therefore,

\:c_{11}=-2,\:\:\:c_{12}=-2

\:c_{21}=5,\:\:\:c_{22}=8

5 0
2 years ago
Read 2 more answers
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