All categories

3 years ago

Please help meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Mathematics

1 answer:

Flura [38]3 years ago

6 0

Answer:

#6 is 17 days

Step-by-step explanation:

This is how I answered it

1) 2750 = 550 + 125x

2) subtract 550 from each side

2750-550=2200

so the left over equation is:

2200 = 125x

3) divide each side by 125 to get x by itself

2200÷125= 17.6

4) you are left with: x = 17 days

You might be interested in

PLEASE HELP !

adell [148]

First what you wanna do is get y by it’s self. To do that is to first add 5 on each side.

-5+3y=-4
+5 +5

3y= 1

Than you divide 3 on each side and it would give you y=1/3 if it’s a fractions problem but if you looking for decimals you would have to divide 1 by 3 which gets you .33333333.

7 0

3 years ago

Brandon was playing a video game where he scores three points for each treasure he finds. If he found 32 treasures on the first

ratelena [41]

Answer:

300 points

Step-by-step explanation:

32 treasures means he has 32*3 points which is 96 points.

68 treasures means he has 68*3 points which is 204 points.

96+204 is 300

5 0

2 years ago

Write the equation of the line that passes through points (-7,8) and (4,-5)

Alex

Answer:

y=-3/11x+67/11

Step-by-step explanation:

y-8=-5-8/4--7(x--7)

y-8=-3/11(x+7)

11y-88=-3x-21

11y=-3x-21+88

11y=-3x+67

y=-3/11x+67/11

5 0

3 years ago

Read 2 more answers

Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal

lisabon 2012 [21]

Given the following functions below,

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}$

Factorising the denominators of both functions,

Factorising the denominator of f(x),

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}$

Factorising the denominator of g(x),

$\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}$

Multiplying both functions,