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2 years ago

13

A grocery store has 5 pounds of gronola. one customer buys 2 3rds pounds of gronola and another buys 5 6ths pounds. after these

purchases how much gronla is left.

2 answers:

Kryger [21]2 years ago

8 0

Answer:

3 1/2 Pounds

Step-by-step explanation:

2/3=4/6

4/6+5/6=9/6

30/6-9/6=21/6

Amiraneli [1.4K]2 years ago

8 0

5 - 2/3 - 5/6 = 5/1 - 2/3 - 5/6 = 30/6 - 4/6 - 5/6 = 21/6 = 7/2 = 3 + 1/2

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SashulF [63]

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Hope this helps

8 0

3 years ago

The set of numbers 1, 7, 11, and 36 contains values of m. What value of m makes the equation below true? 4m + 8 = 36

german

Answer:

i think its 7

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th

grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

$S = \{1,1,2,2,2,3\}$

And the probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{6}$

$P(1) = \frac{1}{3}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{6}$

$P(2) = \frac{1}{2}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{6}$

P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>

7 0

3 years ago

I do t know how to do it

Luba_88 [7]

We know: the sum of the angles measures in a triangle is 180°.

Therefore we have the equation:

64° + 75° + α = 180°

139° + α = 180° <em> subtract 139° from both sides</em>

α = 41°

α and ∠2 are Supplementary Angles - they add up to 180°.

α + m∠2 = 180°

41° + m∠2 = 180° <em>subtract 41° from both sides</em>

<h3>m∠2 = 139°</h3>

7 0

3 years ago

Can someone plz help plz show work

aliya0001 [1]

Answer:

<h2>LA = 24 ft²</h2>

Step-by-step explanation:

In the base we have the right triangle. Use the Pythagorean theorem for to calculate the hypotenuse:

$h^2=4^2+3^2\\\\h^2=16+9\\\\h^=25\to h=\sqrt{25}\\\\h=5\ ft$

The Lateral Area is the sum of the areas of three rectangles:

$4\ ft\ \times\ 2\ ft\to A_1=(4)(2)=8\ ft^2\\\\3\ ft\ \times\ 2\ ft\to A_2=(3)(2)=6\ ft^2\\\\5\ ft\ \times\ 2\ \ft\to A_3=(5)(2)=10\ ft^2$

The Lateral Area:

$LA=A_1+A_2+A_3\to LA=8+6+10=24\ ft^2$

8 0

3 years ago