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STatiana [176]
3 years ago
13

What are the solutions to |x + 2| = -13?

Mathematics
2 answers:
Delvig [45]3 years ago
4 0

Answer:

first one is d

second one is c

Step-by-step explanation:

pav-90 [236]3 years ago
3 0
C and d simple formula :)
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In which number does the 5 represent a value 10 times the value represented by the 5 in 35,187
blagie [28]
It would be 50,000 since the 5 in the other number is in the thousands place so just multiply that by 10 in place value.
3 0
2 years ago
How to find the vertex calculus 2What is the vertex, focus and directrix of x^2 = 6y
son4ous [18]

Solution:

Given:

x^2=6y

Part A:

The vertex of an up-down facing parabola of the form;

\begin{gathered} y=ax^2+bx+c \\ is \\ x_v=-\frac{b}{2a} \end{gathered}

Rewriting the equation given;

\begin{gathered} 6y=x^2 \\ y=\frac{1}{6}x^2 \\  \\ \text{Hence,} \\ a=\frac{1}{6} \\ b=0 \\ c=0 \\  \\ \text{Hence,} \\ x_v=-\frac{b}{2a} \\ x_v=-\frac{0}{2(\frac{1}{6})} \\ x_v=0 \\  \\ _{} \\ \text{Substituting the value of x into y,} \\ y=\frac{1}{6}x^2 \\ y_v=\frac{1}{6}(0^2) \\ y_v=0 \\  \\ \text{Hence, the vertex is;} \\ (x_v,y_v)=(h,k)=(0,0) \end{gathered}

Therefore, the vertex is (0,0)

Part B:

A parabola is the locus of points such that the distance to a point (the focus) equals the distance to a line (directrix)

Using the standard equation of a parabola;

\begin{gathered} 4p(y-k)=(x-h)^2 \\  \\ \text{Where;} \\ (h,k)\text{ is the vertex} \\ |p|\text{ is the focal length} \end{gathered}

Rewriting the equation in standard form,

\begin{gathered} x^2=6y \\ 6y=x^2 \\ 4(\frac{3}{2})(y-k)=(x-h)^2 \\ \text{putting (h,k)=(0,0)} \\ 4(\frac{3}{2})(y-0)=(x-0)^2 \\ Comparing\text{to the standard form;} \\ p=\frac{3}{2} \end{gathered}

Since the parabola is symmetric around the y-axis, the focus is a distance p from the center (0,0)

Hence,

\begin{gathered} Focus\text{ is;} \\ (0,0+p) \\ =(0,0+\frac{3}{2}) \\ =(0,\frac{3}{2}) \end{gathered}

Therefore, the focus is;

(0,\frac{3}{2})

Part C:

A parabola is the locus of points such that the distance to a point (the focus) equals the distance to a line (directrix)

Using the standard equation of a parabola;

\begin{gathered} 4p(y-k)=(x-h)^2 \\  \\ \text{Where;} \\ (h,k)\text{ is the vertex} \\ |p|\text{ is the focal length} \end{gathered}

Rewriting the equation in standard form,

\begin{gathered} x^2=6y \\ 6y=x^2 \\ 4(\frac{3}{2})(y-k)=(x-h)^2 \\ \text{putting (h,k)=(0,0)} \\ 4(\frac{3}{2})(y-0)=(x-0)^2 \\ Comparing\text{to the standard form;} \\ p=\frac{3}{2} \end{gathered}

Since the parabola is symmetric around the y-axis, the directrix is a line parallel to the x-axis at a distance p from the center (0,0).

Hence,

\begin{gathered} Directrix\text{ is;} \\ y=0-p \\ y=0-\frac{3}{2} \\ y=-\frac{3}{2} \end{gathered}

Therefore, the directrix is;

y=-\frac{3}{2}

3 0
1 year ago
How do i do #3? I dont know how to do the whole problem.
lisov135 [29]
You have to put the problem down we cant help you if its not there
sorry but please put equation in or problem
3 0
3 years ago
Does the graph represent a linear expression?<br><br> Yes or No<br><br> Please answer fast!
Virty [35]
Yes it does goes over the c axis
3 0
3 years ago
Evaluate the following expression (2.3)-3(1,1)
uranmaximum [27]

Answer:

<em><u>2</u></em><em><u>.</u></em><em><u>3</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>(</u></em><em><u> </u></em><em><u>3</u></em><em><u>,</u></em><em><u> </u></em><em><u>1</u></em><em><u>)</u></em><em><u> </u></em>

Step-by-step explanation:

1) Simplify  3 × (1, 1) 3 × (1, 1)  to  3× 1, 13 × 1,1.

<em>2</em><em>.</em><em>3</em><em> </em><em>-</em><em> </em><em>(</em><em> </em><em>3</em><em> </em><em>×</em><em> </em><em>1</em><em>,</em><em> </em><em>1</em><em> </em><em>)</em>

2) Simplify 3 × 1 to 3.

2.3 - ( 3, 1)

<em><u>Therefor</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>2</u></em><em><u>.</u></em><em><u>3</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>(</u></em><em><u> </u></em><em><u>3</u></em><em><u>,</u></em><em><u> </u></em><em><u>1</u></em><em><u>)</u></em><em><u>.</u></em>

3 0
3 years ago
Read 2 more answers
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