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3 years ago

Sin A 4/5. Find COSA + tan A

Mathematics

2 answers:

Ivahew [28]3 years ago

4 0

Answer:

Step-by-step explanation:

The opposite side (the one not connected to A) = 4

The hypotenuse is 5

The adjacent side needs to be found for the cosine and the tangent.

a^2 + b^2 = c^2

a = opposite side = 4

b = adjacent side = ?

c = hypotenuse = 5

4^2 + x^2 = 5^2

16 + x^2 = 25

x^2 = 25 - 16

x^2 = 9

x = sqrt(9)

x = 3

cos(A) = adjacent / hypotenuse = 3/5

Tan(A) = opposite / adjacent = 4/3

cos(A) + tan(A) = 3/5 + 4/3

cos(A) + tan(A) = 9/15 + 20/15 = 29/15

Andrews [41]3 years ago

3 0

Given: SinA = 4/5

To find: CosA + TanA

Solution:
16/25 + Cos²A = 1 [Sin²A + Cos²A = 1]
Cos²A = 1 - 16/25
Cos²A = 25 - 16/25
Cos²A = 9/25
CosA = 3/5
We know that TanA = SinA/CosA
TanA = (4/5)/(3/5)
TanA = 4/3
CosA + TanA = 3/5 + 4/3 = 29/15

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87 1/2% of what number is 105?

vampirchik [111]

Answer:

120

Step-by-step explanation:

87.5% of what number is 105?

87.5%=0.875

105/0.875=120

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3 years ago

A bullet is fired straight up from a gun with initial velocity 1120 feet per second at an initial height of 8 feet. Use the form

Dafna1 [17]

Answer:

70 seconds

Step-by-step explanation:

Given that;

The initial velocity $v_o$ of the bullet fired = 1120 ft/s

Initial height h = 8 feet

The expression to determine how many seconds it takes the bullet to hit the ground is:

$h = -16t^2 +v_ot + 8$

Thus;

Replacing the value of $v_o$ = 1120 and h = 0 (i.e. when h =0) in the above expression; we have:

$0= -16t^2 +(1120)t + 8$

$= -16t^2 +(1120)t + (8-0)$

= -16t² + 1120t + 8

mulitiply through by (-)

= 16t² -1120t - 8

Divide through by 8

= 2t² - 140t - 1

The above expression forms a quadratic equation.

where;

a = 2

b = -140

c = - 1

So, by using the quadratic formula $\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$ , we have:

$= \dfrac{-(-140) \pm \sqrt{(-140)^2-4(2)(-1)}}{2(2)}$

$= \dfrac{140 \pm \sqrt{19600-(-8)}}{4}$

$= \dfrac{140 \pm \sqrt{19608}}{4}$

$= \dfrac{140 \pm 140}{4}$

$=\dfrac{140+ 140}{4} \ \ \ OR \ \ \ \dfrac{140-140}{4}$

$=\dfrac{280}{4} \ \ \ OR \ \ \ 0$

= 70

Thus, the time (in seconds) it took the bullet to it the ground = 70 seconds

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2 years ago

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topjm [15]

The first option is

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The second option is

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So, neither of them is equivalent to $54x+18$

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3 years ago

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Vlad1618 [11]

75 * 1000/3600 = 20.8333333

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nikdorinn [45]

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