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3 years ago

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Nick had 3 1/4 bottles of water for his wrestling practice. When he finished he had 1 2/4 bottles of water left. He said he used

2 1/4 bottles of water during the practice. Do you agree? Explain.

1 answer:

sweet-ann [11.9K]3 years ago

7 0

1 2/4+2 1/4 ≠ 3 1/4 but 1 2/4+2 1/4 = 3 3/4

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At a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. T

elixir [45]

Answer:

$\text{Exact area of the sidewalk}=40 \pi\text{ m}^2$

$\text{Approximate area of the sidewalk}=125.6\text{ m}^2$

Step-by-step explanation:

We have been given that at a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. The inner edge of the sidewalk is a circle with a radius of 9 m.

To find the area of the side walk we will subtract the area of inner edge of the side walk of lion pen from the area of the outer edge of the lion pen.

$\text{Area of circle}=\pi r^2$ , where r represents radius of the circle.

$\text{Exact area of the sidewalk}=\pi*\text{(11 m)}^2-\pi*\text{(9 m)}^2$

$\text{Exact area of the sidewalk}=\pi*\text{121 m}^2-\pi*\text{81 m}^2$

$\text{Exact area of the sidewalk}=40 \pi\text{ m}^2$

Therefore, the exact area of the side walk is $40 \pi\text{ m}^2$

To find the approximate area of side walk let us substitute pi equals 3.14.

$\text{Approximate area of the sidewalk}=40*3.14\text{ m}^2$

$\text{Approximate area of the sidewalk}=125.6\text{ m}^2$

Therefore, the approximate area of the side walk is $125.6\text{ m}^2$ .

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3 years ago

Write x^2 − 8x + 13 = 0 in the form (x −

padilas [110]

If you would like to write the equation in the above form, you can calculate this using the following steps:

x^2 - 8x + 13 = 0
(x - 4)^2 = x^2 - 8x + 16
(x - 4)^2 - 3 = 0
(x - 4<span>)^2 = 3
</span>
The correct result would be (x - 4<span>)^2 = 3.</span>

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4 years ago

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KengaRu [80]

Answer:

-51.4

Step-by-step explanation:

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What’s the the value of x

Verizon [17]

Answer:

12.5 $\sqrt{3}$

Step-by-step explanation:

30-60-90 triangles always have the height be sqrt3 the base.

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2 years ago

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There are values of t so that sin t=.35 and cos t=.6

NISA [10]

Recall the fundamental rule of trig:

$\sin^2(x)+\cos^2(x)=1 \quad\forall x \in \mathbb{R}$

So, there exists an angle $t$ such that

$(0.6,0.35)=(\sin(t),\cos(t))$

if and only if

$\sin^2(t)+\cos^2(t)=0.6^2+0.35^2=1$

Working out the numbers, we get

$0.6^2+0.35^2=0.36+0.1225=0.4825\neq 1$

So, there doesn't exist a number $t$ such that

$(0.6,0.35)=(\sin(t),\cos(t))$

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3 years ago