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4 years ago

Math Help Please?

1 answer:

3 0

4. There are 13 Clubs in a standard deck of cards so the probability of drawing a club would be 13/52 or 1/4.

5. There is on one 4 of hearts so the probability is only 1/52

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James borrows $300 at an interest rate of 8% and takes 5 years to pay it off.

Eduardwww [97]

He pays $420
0.08*5=120
300+120= $420

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3 years ago

Read 2 more answers

If the slope of a line is 1/2 and the y-intercept is 6, what is the x-intercept of the same line?

ASHA 777 [7]

The slope of a line is the ratio of the change in y to the change in x. The slope of the given line is 1/2 = -6/-12. That is, when y changes by -6 to go from 6 to zero, x will change by -12 to go from 0 to -12.

The x-intercept is (-12, 0).

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4 years ago

the volume of a large sphere (of radius R) is twice the volume of a smaller sphere (of radius r). form an equation linking r and

Sedaia [141]

Step-by-step explanation:

radius of large sphere is R,

then volume is (4/3)*pie*R³

and

the radius of small sphere is r,

then volume is (4/3)*pie*r³

condition is,

volume of larger sphere is twice of the volume of smaller sphere.

then, (4/3)*pie*R³=2*(4/3)*pie*r³;

R³= 2r³

R=(2^⅓)*r

3 0

3 years ago

lara31 [8.8K]

Answer:

The time spent by a physician with a patient

Step-by-step explanation:

Option C is the answer

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2 years ago

In a study of the accuracy of fast food drive-through orders, McDonald’s had 33 orders that were not accurate among 362 orders o

melomori [17]

Answer:

A. We need to conduct a hypothesis in order to test the claim that the true proportion of inaccurate orders p is 0.1.

B. Null hypothesis: $p=0.1$

Alternative hypothesis: $p \neq 0.1$

C. $z=\frac{0.0912 -0.1}{\sqrt{\frac{0.1(1-0.1)}{362}}}=-0.558$

D. $z_{\alpha/2}=-1.96$ $z_{1-\alpha/2}=1.96$

E. Fail to the reject the null hypothesis

F. So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of inaccurate orders is not significantly different from 0.1.

Step-by-step explanation:

Data given and notation

n=362 represent the random sample taken

X=33 represent the number of orders not accurate

$\hat p=\frac{33}{363}=0.0912$ estimated proportion of orders not accurate

$p_o=0.10$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

A: Write the claim as a mathematical statement involving the population proportion p

We need to conduct a hypothesis in order to test the claim that the true proportion of inaccurate orders p is 0.1.

B: State the null (H0) and alternative (H1) hypotheses

Null hypothesis: $p=0.1$

Alternative hypothesis: $p \neq 0.1$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

C: Find the test statistic

Since we have all the info required we can replace in formula (1) like this:

$z=\frac{0.0912 -0.1}{\sqrt{\frac{0.1(1-0.1)}{362}}}=-0.558$

D: Find the critical value(s)

Since is a bilateral test we have two critical values. We need to look on the normal standard distribution a quantile that accumulates 0.025 of the area on each tail. And for this case we have:

$z_{\alpha/2}=-1.96$ $z_{1-\alpha/2}=1.96$

P value

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z$

E: Would you Reject or Fail to Reject the null (H0) hypothesis.

Fail to the reject the null hypothesis

F: Write the conclusion of the test.

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of inaccurate orders is not significantly different from 0.1.

6 0

3 years ago